Return only text after last underscore in JavaScript string

Question

If I have a string like so:

var str = 'Arthropoda_Arachnida_Zodariidae_Habronestes_hunti';

How can I get just the last part of the string after the last underscore?

And in the case there are no underscores just return the original string.

In this case I want just 'hunti'

possible duplicate of How to get the last part of a string in JavaScript? — I Hate Lazy
– I Hate Lazy, Commented Dec 12, 2012 at 2:46

Teddy · Accepted Answer · 2012-12-12 02:46:59Z

31

var index = str.lastIndexOf("_");
var result = str.substr(index+1);

answered Dec 12, 2012 at 2:46

Teddy

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4 Comments

Eli Gassert Over a year ago

IMO prefer this method. The other method requires more memory and more processing. It has to create the array, just to get the last item, and then throw away the rest of the array. Not a huge deal in the example you posted, but this method is two lines instead of one and I think equally as readable and functional. So I'd prefer this answer to the rest.

Peter Olson Over a year ago

This method is less aesthetically pleasing to me, as it feels somewhat verbose, but I willingly admit that it is faster. Unless he has very long strings and he's doing this thousands of times, though, I doubt it will make a perceptible difference.

RobG Over a year ago

@EliGassert—peformance is unlikely to be an issue, but you're correct that substring is much faster than the other methods proposed. It just depends on how the OP wants to approach it.

WebDevNerdStuff Over a year ago

This answer is correct, but you don't need to do the steps separately. str.substring(str.lastIndexOf('_') + 1);

Peter Olson · Accepted Answer · 2012-12-12 02:44:51Z

15

It's very simple. Split the string by the underscore, and take the last element.

var last = str.split("_").pop();

This will even work when the string does not contain any underscores (it returns the original string, as desired).

answered Dec 12, 2012 at 2:44

Peter Olson

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Comments

RobG · Accepted Answer · 2012-12-12 03:03:57Z

4

You can use a regular expression:

'Arthropoda_Arachnida_Zodariidae_Habronestes_hunti'.match(/[^_]*$/)[0];

answered Dec 12, 2012 at 3:03

RobG

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