json parse in javascript

Question

I have the following (snippet) variable:

var txt = {
        'start': {
                 'name':'Call start',
                 'data': {'next':'start/e3fe40'},
                 'id':'start',
                 'type':'standard---start'
        },
        'e3fe40': {
                'name':'Menu',
                'data':  {'next':'end/asd3rg'},
                'id':'e3fe40'
         }
};

I need to parse through the JSON and get info from the 'e3fe40' branch (without knowing how its going to be called.

Here's what I have:

var nxt = txt.start.data.next.substr(6,10); <-- works
console.log(nxt);                           <-- works
console.log(txt.start.data.next);           <-- works
console.log(txt.nxt.name);                  <-- nxt should contain 'e3fe40'

So, how do I go down a branch? txt.nxt.name won't work, txt.{nxt}.name won't work, etc....

Thanks, Dan

Also the word for what you're doing isn't "parse", if we're picking nits. :-) You need the [ ] operator. — Pointy
– Pointy, Commented Aug 13, 2012 at 16:33
You're always going to struggle if you don't know the structure of your incoming data. All you can do is loop over the keys and try to identify what you want that way, but this is far from ideal. — Mitya
– Mitya, Commented Aug 13, 2012 at 16:34
txt.nxt should be txt.e3fe40 .. I was trying to substitute e3fe40 with nxt as variable, but dont know how — Dan
– Dan, Commented Aug 13, 2012 at 16:34
Quentin: the js object literal is initially json received from another app -- i'm posting like this to shorten the code — Dan
– Dan, Commented Aug 13, 2012 at 16:36

Diode · Accepted Answer · 2012-08-13 16:34:14Z

2

var key = txt.start.data.next.substr(6);
console.log(txt[key].name);

answered Aug 13, 2012 at 16:34

Diode

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Comments

Subir Kumar Sao · Accepted Answer · 2012-08-13 16:37:14Z

0

Assuming nxt = "e3fe40" you get the value by doing.

txt[nxt].name

Different ways of accessing the values,

txt.e3fe40.name txt['e3fe40'].name and one shown above.

txt.nxt.name is wrong. Because nxt is not a key in the Javascript object,

answered Aug 13, 2012 at 16:37

Subir Kumar Sao

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ARIF MAHMUD RANA · Accepted Answer · 2012-08-13 16:56:21Z

0

If You debug code by using debugging tool and put this code I think it will solve your problem

alert(txt.e3fe40.name);

answered Aug 13, 2012 at 16:56

ARIF MAHMUD RANA

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