Solution for 3225.Maximum Score From Grid Operations#5247
Solution for 3225.Maximum Score From Grid Operations#5247Abhijit-Gautam wants to merge 1 commit into
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Added detailed explanation and implementation for the maximum score problem using dynamic programming and prefix sums.
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3. 其它补充新增题解及代码时,需要创建 Solution.xxx 源代码文件(如果已存在,请确认算法是否更优,是则覆盖已有算法代码),同时,需要在 README.md 以及 README_EN.md 中添加对应的代码片段(英文文件中不要出现中文注释) 🤭 Thank you for your contribution. Please check if your changes comply with the following project specifications. 1. FormattingWe use different formatting tools for various programming languages (including documentation) in our project. You must ensure that the code and documentation are correctly formatted before submitting a pr.
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3. Other notesWhen adding solutions and code, you need to create a Solution.xxx source code file (if it already exists, please confirm whether the algorithm is better, if yes, overwrite the existing algorithm code), and at the same time, you need to add the corresponding code snippets in README.md and README_EN.md (do not have Chinese comments in the English file) |
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Pull request overview
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Adds a full written explanation and multi-language reference implementations for LeetCode 3225 using a DP + prefix-sum approach.
Changes:
- Documented the DP state, transition, and optimization using prefix/suffix maxima.
- Added complete reference solutions for Python, Java, C++, Go, and TypeScript.
- Standardized solution framing around “Dynamic Programming + Prefix Sum”.
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| func maximumScore(grid [][]int) int64 { | ||
| n := len(grid) | ||
| const NEG = math.MinInt64 / 2 | ||
| prefix := make([][]int64, n) |
| We define $\textit{dp}[h_1][h_2]$ as the maximum score for columns $0\ldots j$, where $k[j] = h_1$ and $k[j-1] = h_2$. | ||
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| **Transition** (choosing $k[j+1] = hp$): | ||
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| $$\textit{dp\_new}[hp][h_1] = \max_{h_2}\left(\textit{dp}[h_1][h_2] + \max\left(0,\ \textit{prefix}[j][\max(h_2, hp)] - \textit{prefix}[j][h_1]\right)\right)$$ |
| ``` | ||
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| #### Go | ||
| #### GO |
| for h in range(n + 1): | ||
| dp[h][0] = 0 | ||
| for j in range(n - 1): | ||
| new = [[NEG] * (n + 1) for _ in range(n + 1)] |
| v1 := int64(NEG) | ||
| if prefMax[hp] != NEG { v1 = prefMax[hp] + rc } |
Added detailed explanation and implementation for the maximum score problem using dynamic programming and prefix sums.