Is there a constant variable in awk, that store today's date? If not, is there a way that can store today's date for daily use?

Let's say we have below file:

boo,foo,2016-08-30
foo,boo,2016-07-31

And I need to compare the date $3 in the file, with today's date, regardless what it is.

i.e below script

awk -F, '{if($3>"2015-08-23"){print $0}}'

where 2015-08-23 will be changed by the current date.