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edited Sep 23, 2022 at 10:39

Is there a constant variable in awk, that store today's date? if noIf not, is there a way that can store today's date for daily use?

let'sLet's say we have below file:

boo,foo,2016-08-30
foo,boo,2016-07-31

boo,foo,2016-08-30
foo,boo,2016-07-31

And I need to compare the date $3 in the file, with today's date, regardless what it is.

i.e below script:

awk -F, '{if($3>"2015-08-23"){print $0}}'

awk -F, '{if($3>"2015-08-23"){print $0}}'

Wherewhere 2015-08-23 will be changed by the current date.

Is there a constant variable in awk, that store today's date? if no, is there a way that can store today's date for daily use?

let's say we have below file:

boo,foo,2016-08-30
foo,boo,2016-07-31

And I need to compare the date $3 in the file, with today's date, regardless what it is.

i.e below script:

awk -F, '{if($3>"2015-08-23"){print $0}}'

Where 2015-08-23 will be changed by the current date.

Is there a constant variable in awk, that store today's date? If not, is there a way that can store today's date for daily use?

Let's say we have below file:

boo,foo,2016-08-30
foo,boo,2016-07-31

And I need to compare the date $3 in the file, with today's date, regardless what it is.

i.e below script

awk -F, '{if($3>"2015-08-23"){print $0}}'

where 2015-08-23 will be changed by the current date.

text-processing awk gawk

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occurred Aug 25, 2015 at 14:01

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asked Aug 23, 2015 at 17:34

Current date in awk

Is there a constant variable in awk, that store today's date? if no, is there a way that can store today's date for daily use?

let's say we have below file:

boo,foo,2016-08-30
foo,boo,2016-07-31

And I need to compare the date $3 in the file, with today's date, regardless what it is.

i.e below script:

awk -F, '{if($3>"2015-08-23"){print $0}}'

Where 2015-08-23 will be changed by the current date.

text-processing awk gawk

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