What is the command that launches the whisker menu in the Linux Mint xfce edition. For another distribution that used xfce it was xfce4-popup-whisker menu but that doesn't seem to work. I would like to assign the super key to launch the menu.
3 Answers
It's indeed xfce4-popup-whiskermenu.
However the command is only available from a certain version of the whisker menu. Most probably that other distribution had a newer version of it.
Check your currently installed version in the application manager. The newest is 1.1.1, which contains the popup command.
Follow the instructions here to get the newest version:
- Open Settings Manager -> Keyboard -> Application Shortcuts, click "Add"
- In the "command" field, enter
xfce4-popup-whiskermenu - In the next dialog window, press Super_L (The left "Windows" key)
-
Note that if you set just the Windows (Super) button for that command you will not be able to use Super in other commands. More kere: forum.manjaro.org/t/cant-switch-windows-with-super-tab/2406 and namely my reply there (forum.manjaro.org/t/cant-switch-windows-with-super-tab/2406/…). I would recommend Super-Space and/or Ctrl-Space, Alt-Space.user32012– user320122017-03-10 11:47:54 +00:00Commented Mar 10, 2017 at 11:47
More generally, xfce uses the common method of invoking the command using the name of the associated binary. On my system there are a bunch of them including xfce4-popup-whiskermenu in usr/bin/ You can find it on your system by poking around or using
locate xfce4-popup-whiskermenu
on a command line.
They all seem have man pages so, for example, you can find out about the usage of the xfce4-popup-whiskermenu with the command
man xfce4-popup-whiskermenu
You are not limited to binding only xfce commands to keystrokes, and can start any program using the same command you would use in a terminal.
