How to sort correctly the processes hungry of ram?

Question

With this cmd line I see processes and use of ram in mb

ps aux | awk '{print $6/1024 " MB\t\t" $11}' | sort -rn|less

The problem is the sort

9.95703 MB      /usr/lib/systemd/systemd-journald
9.89062 MB      /usr/sbin/winbindd
9.76953 MB      /usr/sbin/winbindd
9.69922 MB      php-fpm:
9.69922 MB      php-fpm:
9.69531 MB      php-fpm:
9.69531 MB      php-fpm:
9.69531 MB      php-fpm:
93.4297 MB      db_arc1_FREE
9.31641 MB      winbindd:
9.31641 MB      /usr/sbin/snmpd

How to sort correctly so the output became like this?

93.4297 MB      db_arc1_FREE
9.95703 MB      /usr/lib/systemd/systemd-journald
9.89062 MB      /usr/sbin/winbindd
9.76953 MB      /usr/sbin/winbindd
9.69922 MB      php-fpm:
9.69922 MB      php-fpm:
9.69531 MB      php-fpm:
9.69531 MB      php-fpm:
9.69531 MB      php-fpm:
9.31641 MB      winbindd:
9.31641 MB      /usr/sbin/snmpd

Answer 1

ps aux --sort=rss

or

ps aux --sort=%mem