Curl exit immediately if no internet

Question

I want to fetch some apis from github.

so this is the code

array=(link1 link2 link3 link4)
readarray -t item < <(for i in ${array[@]}
      do curl -s "$i" | jq '.tag_name'
      done)

and then I can fetch the data from the item.

But the problem is if there is some links left to fetch, curl just stuck there.

I want it to exit immediately and instead of previous data, I need it to print some text like "error" or get its exitcode so that I can implement some logic in case of any fail.

provide a efficient solution for this.

Freddy · Accepted Answer · 2023-01-29 22:50:09Z

You could read all URLs with one curl invocation and use option --fail-early to exit immediately on the first detected transfer error. Add --max-time to abort each transfer after x seconds and --connect-timeout if you want to restrict the connection time.

The item array will be empty in case of an error, you could check that.

urls=(link1 link2 link3 link4)
readarray -t item < <(
    curl -s --fail-early --connect-timeout 10 --max-time 120 "${urls[@]}" |
    jq '.tag_name')

if [ "${#item[@]}" -eq 0 ]; then
    echo "Uh, failed to fetch data." >&2
    exit 1
fi

telometto · Accepted Answer · 2023-01-29 18:26:11Z

1

You can use curl -f option to exit immediately if the response code is greater than or equal to 400. Also, you can add the -w option to capture the exit code and -o option to redirect the output to /dev/null to avoid printing the response to the console.

array=(link1 link2 link3 link4)

for i in "${array[@]}"
do
    response=$(curl -f -w '%{http_code}' -o /dev/null "$i")
    if [ "$response" -ge 400 ]; then
        echo "error"
    else
        curl -s "$i" | jq '.tag_name'
    fi
done

answered Jan 29, 2023 at 18:26

telometto

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