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OpenVMS DCL command DIRECTORY/NOHEADING displays just the full file name including path info in a single-column format without any of the normal headings for a directory listing. The /NOTRAILING switch removes the normal trailing total info that is displayed.

What is Linux for OpenVMS DIR/NOHEADING/NOTRAILING?

This example directory command from MYHOME:[MYDIR.SUBDIR] shows the complete file names including path info with no other info like size, date, headings and totals:

$ dir/noheading/notrailing
MYHOME:[MYDIR.SUBDIR]ABC.C;3
MYHOME:[MYDIR.SUBDIR]ABC.OBJ;3
MYHOME:[MYDIR.SUBDIR]ABC.EXE;3
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    Some ls flags, I guess. Please show us some sample output from DIR /NOHEADING, most people don't know VMS. Commented Feb 4, 2013 at 23:34
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    @Gilles, the "device" and "directory" information isn't available in ls. And IIRC, VMS has a 2 (or 3?) deep fixed directory structure. Just way too different in concept. What does OP really need to know, and why? Commented Feb 4, 2013 at 23:37
  • @vonbrand, Normally one does not reference a device in file name but one can and yes, in that case, the syntax is different than on Linux systems but the question is not about the file naming conventions. Someone changed the tag on the question to be 'ls' but that was an error. The question is not specifying specific Linux commands. Initially in 1977 on 32-bit VAX hardware there was an 8 level limit on directories. OpenVMS on Alpha and I64 64-bit hardware there is no limit on the number of directory levels. Commented Feb 5, 2013 at 0:30
  • @C.W.HolemanII: Okay, so, what do you want to see? Are you interested in the information (the device on which a file resides + full pathname) or in the formatting? Commented Feb 5, 2013 at 0:37
  • The problem with this question is its lack of context. With a background in Microsoft/IBM/JP Software command interpreters, one will be familiar with things like the /f, /k, and /m options to the (JP Software) dir command and the default output format that they modify. But a Unix/Linux readership is not necessarily familiar with these notions. Commented Jul 19, 2018 at 15:19

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There is no ls command which will show full path information, because VMS and Unix are very conceptually different here. Files are data in the filesystem and filenames are effectively pointers to that data, not containers for the data. So, out of context, the names don't really have path information.

Also, by default, ls doesn't show any header or footer information. It might be that ls -1, which shows all of the files in the current directory in a single column is what you want. (Or, to carry what I said in the first paragraph, you could try ls -1i, which will give you the inode number of each file — a sort of unique identifier for the actual data in the filesystem. But you probably don't really want that.)

Alternately, you could try something other than ls:

find $(pwd) -maxdepth 1

will print out all of the filenames in the current working directory, one per line, with the current working directory prepended. )Add -mindepth 1 too, to leave out the directory itself, if need be.) Maybe that's what you want?

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    find $(pwd) -maxdepth 1 is it. Other than someone putting an 'ls' tag on the question I do not know why that has gotten so much attention. Commented Feb 6, 2013 at 4:08
  • From en.wikipedia.org/wiki/Files-11, the main filesystem for OpenVMS. en.wikipedia.org/wiki/File:Files11_directory_hierarchy.svg shows an example of directories in a filesystem which is organised in a directed acyclic graph (DAG) structure. Rather than inodes, files on a Files-11 disk (or volume set) have a unique file identification (FID) which indexes into the INDEXF.SYS file where metadata for the file is located. Commented Feb 6, 2013 at 4:37
  • @C.W.HolemanII Okay, but I still don't know exactly what you're trying to accomplish here. :) Commented Feb 6, 2013 at 20:37
  • A list of complete file names including the path such as this answer (the one with the green check) produces. Commented Feb 6, 2013 at 23:40
  • @C.W.HolemanII Apparently. But that's still not at all clear from the question, even though it seems like my answer does it for you. Commented Feb 7, 2013 at 16:57

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