How to strip off certain hexadecimal characters in Bash?

Question

I have gathered a wordlist for person to follow on twitter. However, there is a problem. When i cat and do xxd a extra hidden characters are found. i.e 1b5b 6d1b 5b4b . I need to strip those character. Lets say 007_sharky is name , when i cat it i get 00000000: 3030 375f 7368 6172 6b79 1b5b 6d1b 5b4b 007_sharky.[m.[K 00000010: 0a

But i need to get

00000000: 3030 375f 7368 6172 6b79 0a 007_sharky.

Its not for only one line for multiple line, so i can do

cat file | while read line; do
something 
done

I m missing the something part, how can i remove those character. Also i deleted the file mistakely again after formatting using cut awk and grep again i got this. Also the first pic is new one and second pic is old one.

https://gist.github.com/machinexa2/293823309ad804866b32b59eda17526d

Answer 1

Looks like there are exactly 6 extra bytes at the beginning of each line. So you can use this:

cut -b 7- temp > result