I have file consisting of a single line of text. I am trying to obtain the strings between the "#" and "@" symbols and store them as a newline on "Sequence.txt".
For example, I have the input line:
#HelloMyName@#IsAdam@#NiceToMeetYou@
The expected output should be:
HelloMyName
IsAdam
NiceToMeetYou
I have tried the command: following line of code:
sed 's/.*#\(.*\)@.*/\1/' >> Sequence.txt
However, the output is exactly the input:
#HelloMyName@#IsAdam@#NiceToMeetYou@
This will work with the gnu version of sed ( by default on every linux )
echo -n '#HelloMyName@#IsAdam@#NiceToMeetYou@' | sed 's/#\([^@]*\)@/\1\n/g'
give me
HelloMyName
IsAdam
NiceToMeetYou
On macos
echo -n '#HelloMyName@#IsAdam@#NiceToMeetYou@' | sed 's/#\([^@]*\)@/\1\'$'\n''/g'
These are examples with echo the same will work files .
echo -n '#HelloMyName@#IsAdam@#NiceToMeetYou@' > input.txt
sed 's/#\([^@]*\)@/\1\n/g' input.txt > sequence.txt
With GNU awk (gawk), using FPAT to define a field as a sequence of non-#@ characters:
$ gawk '{$1=$1} 1' FPAT='[^#@]+' OFS='\n' file >> Sequence.txt
$
$ tail Sequence.txt
HelloMyName
IsAdam
NiceToMeetYou
Similar approach, in perl:
perl -lpe '$_ = join "\n", /[^#@]+/g' file >> Sequence.txt
This sequence:
[^#]* # Accept some string of characters that are **not** the start character.
# # Followed by an start character #
[^@]* # Followed by an string of **not** ending characters.
@ # Followed by an ending character.
Repeated several times would capture (almost) the whole line.
Like this:
s/[^#]*#\([^@]\)@/\1\n/g
That will convert the input line into several lines as requested.
The only thing missing is to erase what may remain.
sed 's/[^#]*#\([^@]*\)@/\1\n/g;s/\(.*\)\n.*$/\1/'
Assumes that # @ # @.... occur in this order.
$ perl -lne 'print for /#(.*?)@/g' file
Posix Sed:
° turn all @ to newlines, guaranteed to not be present.
° Then shave off upto the leading #.
° Thereby uncovering the element to be printed.
.
$ sed -e '
y/@/\n/
s/^[^#]*#//
P;D
' file
