I am trying to write this command on UNIX:
ls -l | sed 'p/^.rwx'
But I get the following error:
sed: -e expression #1, char 2: extra characters after command
I'm trying to print the files/dirs in which the user has all the permitions (rwx)
3 Answers
Your print command needs to come at the end, and you also want to suppress printing by default:
ls -l | sed -n '/^.rwx/p'
If you're on a system with the stat command, there's another way to solve the problem:
for f in *
do
stat -c "%a" "$f" | grep -q ^7 && printf "%s\n" "$f"
done
It's dangerous to rely on the output of ls; consider someone who created a file like this:
touch $'foo\n-rwx some file'
... that will create a separate line in the ls output that (falsely) matches the regular expression. Using a shell glob (*) avoids that issue.
Yet another way is to use find:
find . ! -name . -prune -perm -700 -ls
-
I don't encourage using
lsfor anything other than human consumption but for the record (and contrary to popular belief) there are cases when you can safely "parse"lsoutput - this is just one of them (another one that comes to mind is when you want to count items in a directory). So, you can simply dols -lq | sed '/^.rwx/!d'and it will work with any kind of file name.don_crissti– don_crissti2017-05-10 17:19:48 +00:00Commented May 10, 2017 at 17:19 -
good point with the
-qflag -- that gets around the filename issue. Thanks, Don!2017-05-10 17:27:39 +00:00Commented May 10, 2017 at 17:27
For your specific problem, consider using
find . -perms 700 -maxdepth 1 -ls
or
find . -perms /u+rwx -maxdepth 1 -ls
-
this will recurse subdirectories (different from their original
ls -l) and I think you want-700and maybe-ls, to emulate the originalls -lbehavior.2017-05-10 15:31:43 +00:00Commented May 10, 2017 at 15:31 -
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@JeffSchaller: good points. Updated my answer to include
-maxdepth 1and-ls.thiagowfx– thiagowfx2017-05-10 17:32:56 +00:00Commented May 10, 2017 at 17:32 -
@M.T ok, I just provided an alternative because you didn't specify it was a requirement to use
sed.thiagowfx– thiagowfx2017-05-10 17:34:22 +00:00Commented May 10, 2017 at 17:34
You want to run this:
ls -l | sed -n '/^.rwx/p'
n -> Prints only matching data
^.rwx -> Starting with any character but followed by rwx.
p -> Print the data
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1Can you please explain your answers, add some detailsRomeo Ninov– Romeo Ninov2017-05-10 19:03:23 +00:00Commented May 10, 2017 at 19:03
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ls -l | sed -n '/^.rwx/p' n -> Prints only matching data ^.rwx -> Starting with any character but followed by rwx. p -> Print the dataMurali Mohan– Murali Mohan2017-05-25 07:29:11 +00:00Commented May 25, 2017 at 7:29
/pgoes at the end of the sed command, not the beginning.sed -n /pattern/ p