Using multiple wildcards in one glob

Question

In my directory, I have a list of files with different extensions such as

file-abc-12.out
file-abc-12.csv
file-abc-12.txt
file-xyz-12.out
file-xyz-12.csv
file-xyz-12.txt
file-abc-04.out
file-abc-04.csv
file-abc-04.txt
file-xyz-04.out
file-xyz-04.csv
file-xyz-04.txt

If I only want to list the files that contain abc and end in a .out, how would I do that. I want to perform a ls or a find using two pattern matching searches *abc* and *out. I only know how to search one or the other at a time, how would I have it search for file names with both conditions?

Answer 1

This will give you what you want:

$ find . -name '*abc*' -o -name '*out'

Answer 2

I'm interpreting the "and" used in the question as a strict "logical and", i.e. as "find files whose names match both *abc* and *out".

You may use multiple wildcards in one filename globbing pattern:

$ ls *abc*out

or

$ find . -type f -name "*abc*out"

for example.

The pattern *abc*out would match any name containing the string abc and then ending in out.

If no file matches the pattern, the pattern will be left unexpanded. If that happens, ls will get the pattern *abc*out as the argument rather than a valid filename, and will complain about ls: cannot access *abc*out: No such file or directory.

To make bash display an error about not being able to expand a file globbing pattern rather than passing the unexpanded pattern to ls, set the failglob shell option:

bash-4.4$ ls *abc*out
ls: *abc*out: No such file or directory

bash-4.4$ shopt -s failglob

bash-4.4$ ls *abc*out
bash: no match: *abc*out

Answer 3

The solution I found to work for me involved using grep. It follows:

$ ls *out | grep "abc"