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I have a script scriptA.sh that if a variable assume a certain value, it has to execute another script scriptB.sh that execute something and then call a scriptA.sh, that will call a scriptB.sh and so on.

I draw the execution: 

ScriptA - ScriptB         
   |
   |
   _
            |
            _
   |
   |
   _
            |
            _

I have tried in this way but process are never closed

ScriptA.sh
./scriptB.sh &
exit

ScriptB.sh
./scriptA.sh &
exit

And also this way but process are never closed

ScriptA.sh
./scriptB.sh && exit

ScriptB.sh
./scriptA.sh && exit

Any suggestion?

The actual scripts:

scriptA.sh:

#!/bin/bash
val=123
directory_path=`pwd`
script_name=$0
if [ $val -eq 123 ];then
  echo "call B and exit"
  ./scriptB.sh $directory_path $script_name && exit 0
fi

scriptB.sh:

#!/bin/bash
directory_path=$1
exec_command=$2
cd
cd $directory_path
echo "call A and exit"
$exec_command && exit 0
Improve this question
5
  • You don't have a proper end condition on the recursion? Commented Jan 30, 2017 at 12:22
  • 1
    can you add the actual bash-code to your question? Commented Jan 30, 2017 at 13:13
  • @Kusalananda no I haven't a proper end condition: ScriptA is in a while true loop and if a value is over the threshold then ScriptA call ScriptB and terminate. The ScriptB execute, then call ScriptA and terminate. Commented Jan 30, 2017 at 13:21
  • @MichaelD. scriptA.sh #!/bin/bash val=123 directory_path=`pwd` script_name=$0 if [ $val -eq 123 ];then echo "call B and exit" ./scriptB.sh $directory_path $script_name && exit 0 fi scriptB.sh #!/bin/bash directory_path=$1 exec_command=$2 cd cd $directory_path echo "call A and exit" $exec_command && exit 0 Commented Jan 30, 2017 at 13:25
  • nice endless loop. exit will never be called Commented Jan 30, 2017 at 13:36

1 Answer 1

Reset to default
0

Update: To keep your structure, you might create these two files:

scripta.sh

#!/bin/bash
./controller.sh a

scriptb.sh

#!/bin/bash
./controller.sh b

Here is a suggestion to make it easier:

controller.sh

#!/bin/bash
# run   ./controller.sh a   to run a/b
# run   ./controller.sh b   to run b/a
if [ "$1" == "a" ]; then
  ./ascript.sh      
  ./bscript.sh

elif [ "$1" == "b" ]; then
  ./bscript.sh
  ./ascript.sh
else
  echo "choose a or b ./controller.sh [a|b]"
  exit 255
fi
exit 0

ascript.sh

#!/bin/bash
echo "script a"
# add code here

bscript.sh

#!/bin/bash
echo "script b"
# add code here
Improve this answer
2
  • Thank you for the answer but this isn't useful for me because I can't change the script structure with the insertion of a controller... Commented Jan 30, 2017 at 14:18
  • edited/updated my answer: "Do One Thing and Do It Well" and "Keep it Simple, Stupid." are some *nix rules which you might want to follow. Commented Jan 30, 2017 at 14:27

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