awk to print underscore

Question

I need awk to print underscore in the output. see below example

Current Output

  [root@looct ~]# date | awk '{print $2$3$6}'
   Nov142016

Required Output

Nov_14_2016   -----> I need this, is it possible?

icarus · Accepted Answer · 2016-11-17 05:15:43Z

6

date +%b_%d_%Y

will do it without an extra process.

answered Nov 17, 2016 at 5:15

icarus

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Thor · Accepted Answer · 2016-11-17 07:27:20Z

3

 date | awk '{print $2"_"$3"_"$6}'

or with OFS

date | awk -v OFS=_ '{print $2,$3,$6}'

Thor

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answered Nov 17, 2016 at 5:09

Baba

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2 Answers 2