bash shell loop through directory listing contents and executability

Question

I'm currently working on a homework assignment and I need to take a given directory path and from that list the files and directories in it. While also including if it's executable or not. I'm also restricted by not being allowed to use any other languages except bash.

My original thought was to use ll and cut to get what I needed but I couldn't seem to get it to work. Then I was thinking I could use something like (not working, just an idea)

read input
for f in $input
do
if [[ -x "$f" ]]
then
echo "$f is executable"
else
echo "$f is not executable"
fi
done

I need the output to be something like and I'm not sure how to get there

file-name1 is executable

file-name2 is not executable

directory1 is executable

Answer 1

Try like

my=($(ls -la $dr |awk {'print $9'}))  
echo ${my[@]}  
for i in "${my[@]}"  
do  
    if [[ -x "$i" ]]  
    then  
        echo "File '$i' is executable"  
    else  
        echo "File '$i' is not executable or found"  
    fi  
done                   

Answer 2

You're taking a directory and then checking to see whether the directory itself is executable, and not looking into its contents as you want to.

read input
for f in ${input}/*; do
    echo -n "$f is "
    type=""
    if [[ -x "$f" ]]; then
        type="executable"
    else
        type="non-executable"
    fi
    if [[ -d "$f" ]]; then
        type="$type directory"
    fi
    echo "$type"
done

Making sure the value of $input is a readable directory is an exercise I shall leave for you.