I'm looking for a way to display the filename when using this command:
cat *.tcp | grep "tcp" | grep "open" | sort | uniq
Is there a way to do it?
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2 Answers
grep tcp *.tcp | grep open | sort -u
Giving multiple filenames to grep will, by default, cause grep to prefix the matching output lines with the filename(s) they matched in. The only other change I made was to combine sort | uniq into sort -u (and to remove the quotes that are unnecessary here).
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1+1 although I think it has the potential for false matches if any of the filenames matches the pattern
open: maybe that's not an issue in this particular application - otherwise perhaps consider replacing the secondgrepby an awk e.g.awk -F: '$2 ~ /open/'?steeldriver– steeldriver2015-07-08 17:41:40 +00:00Commented Jul 8, 2015 at 17:41 -
fair point on the filename possibly matching, although the OP's question implied that filenames would become part of the pipeline regardless. The awk statement you have now wouldn't quite work; it's only matching against field 2, and would miss matches in fields 3 & on.2015-07-08 18:04:03 +00:00Commented Jul 8, 2015 at 18:04
grep -H 'tcp'
-H, --with-filename Print the file name for each match. This is the default when there is more than one file to search.
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2How would I incorporate this into my command and keep the formatting of the columns that my command gives me?Proletariat– Proletariat2015-07-08 16:24:00 +00:00Commented Jul 8, 2015 at 16:24