Command-line parameters in bash script not recognised

Question

I use Debian (Raspbian) Wheezy. If this command line works fine:

smsd -c sms/out -i 60 -0 -f sms/smsd.log

and this alias also works fine:

bsmsd='smsd -c sms/out -i 60 -0 -f sms/smsd.log'

then why does this self-same command line in an executable bash script start the command smsd, but does not see any of the parameters I'm specifying? This is the script:

#!/bin/bash

smsd -c sms/out -f /home/pi/sms/smsd.log -i 60 -0 -v

I've tried redirecting and piping, to no avail.

I'm invoking the script (it's called ssmsd) from the command line like so:

./ssmsd

After that, this is the output from ps -fC smsd:

UID        PID  PPID  C STIME TTY          TIME CMD

Edit: I know it doesn't recognise the parameters, because it tells me I didn't specify a spooling directory. But I did: -c sms/out. When called from the script, it gives version number and author, and exits.

Perhaps I should add: it calls itself a daemon, but it's not a well-behaved daemon. You can't smsd start|stop|restart it, and it doesn't run in the background. So if I call it from a command line (or with that alias) and then start another terminal and do ps -fC smsd, I get:

UID        PID  PPID  C STIME TTY          TIME CMD
pi        2860  2621  0 17:49 pts/0    00:00:00 smsd -c xxxxxxx -i 60 -0 -f sms/smsd.log

Answer 1

This looks rather obvious, you're not using the same arguments.

If this is gnokii-smsd and you specify -v, just like you're specifying in the script version it should print version and exit, just like you told it does.

Why haven't you tried with the exact same arguments when in shell mode than in script mode?