Print on screen at a certain string of numbers

Question

I want to extend the functionality of a part of a program that I'm working now..

Right now my code prints this on screen:

1
2
3
4
5
6
7
8
9
10
11
12
13
14
...
1999

But I'm looking to do this: Putting the tens in text, without number. Also, numbering tens.

1
2
3
4
5
6
7
8
9
ten 1
11
12
13
14
15
16
17
18
19
ten 2
21
22
...
1999

But with the functions that I know of C, I can't figure how to do. Could do this with many ifs in the for, but do not want a code so extensive.

The code of the first output is this:

#include<stdio.h>

int main(void) {

    int i, j=2000;

        for(i=1;i<=j;i++)
        {
            printf("%d\n", i);

        }

    return 0;
}

Very simple, and I want to keep that.

IN SIMPLE WORDS: All numbers ending in 0, should be print "ten x", instead the number...

Thank you.

Answer 1

To find out if a number n is divisible by ten, you use:

if ((n % 10) == 0) ...

That's the modulo operator which returns the remainder when n is divided by ten - numbers divisible by ten have a remainder of zero when you do that, all other numbers have a remainder of one through nine (at least in the non-negative space which is where you're working - it may be different for negative numbers but I'm not going to check since it's not relevant here).

To find which number you need to output with your "ten" string, simply divide n by ten.

So you print statement will become something like:

if ((i % 10) == 0)
    printf ("ten %d\n", i / 10);
else
    printf ("%d\n", i);

Making that change gives you the output:

1
2
3
4
5
6
7
8
9
ten 1
11
12
:
1988
1989
ten 199
1991
1992
1993
1994
1995
1996
1997
1998
1999
ten 200

which appears to be what you're after.

---

And just one other point, your output appears to stop at 1999 rather than 2000, despite the code. If that's what you really want, either change j to be 1999 or change the for statement to use < instead of <=.

Answer 2

    #include <stdio.h>
    int main(void)
    {
      int i, j=2000;
      for( i = 1; i <= j; i++ )
      {
        if ( !i%10 ) // if i / 10 is an integer...
        {
          printf ("ten %d\n", i/10);
        } else
        {
          printf("%d\n", i);
        }
      }
      return 0;
    }

Answer 3

First, you may want to check IF the number is divisible by 10. Look here how to do that: Check if a double is evenly divisible by another double in C?

you could then check how many times it could be divided by 10 and print them out