suggest we have an array of class A's objects, and class A's constructor require two arguments, like this:
class A
{
public:
A( int i, int j ) {}
};
int main()
{
const A a[3] = { /*How to initialize*/ };
return 0;
}
How to initialize that array?
Say:
const A a[3] = { {0,0}, {1,1}, {2,2} };
On older compilers, and assuming A has an accessible copy constructor, you have to say:
const A a[3] = { A(0,0), A(1,1), A(2,2) };
C++ used to be pretty deficient with respect to arrays (certain initializations just were not possible at all), and this got a little better in C++11.
-std=c++0x. Accessible means that you can access it, i.e. it's not private or =deleted.=delete ?As long as the type has a copy constructior (whether synthesized or explicitly defined) the following works:
A array[] = { A(1, 3), A(3, 4), A(5, 6) };
This work both with C++2003 and C++ 2011. The solution posted by KerrekSB certainly does not work with C++ 2003 but may work withC++ 2011 (I'm not sure if it works there).
you can provide a default constructor and initialize your array as normal. After successful initialization, use a loop to reassign values to each member
i think it should be like this
const A a[3] = { A(1, 2), A(3, 4), A(5, 6) };
