PHP json_encode won't output proper result

Question

I want to output users via a json object but when I try to output their songs list it only outputs the last one. I want to get this list into an array.

this is my array push while looping through users,

array_push($arrayUsers, array(
               'username' => $user['username'],
               'id' => $user['_id'],
               'favSongs' => array(
                    'title' =>'song1',
                    'title' =>'song2'
                    )
               )
          );

but this is what I get back (missing song title),

[{"username":"asdfasdfasd","id":{"$id":"4f58d7227edae19c02000000"},"songs":{"title":"song2"}}]

I want it to output the songs like this, but am confused how to get it to do this using PHP:

"songs":[{"title": "song1"}, {"title": "song2"}]

array('title' =>'song1','title' =>'song2') is not a valid array - or rather it is valid but you cannot have two of the same key without always overwriting one. — Michael Berkowski
– Michael Berkowski, Commented Mar 9, 2012 at 19:58
Instead, just use a plain numeric array for those 'favSongs' => array('song1','song2') — Michael Berkowski
– Michael Berkowski, Commented Mar 9, 2012 at 19:59
ohhh I get it now! Thanks I tried this and it worked array_push($arrayUsers, array('username' => $user['username'], 'id' => $user['_id'], 'favSongs' => array(array('title' =>'song1'), array('title' =>'song3')))); — jamcoupe
– jamcoupe, Commented Mar 9, 2012 at 20:01

gen_Eric · Accepted Answer · 2012-03-09 19:59:40Z

3

'favSongs' => array(
   'title' => 'song1',
   'title' => 'song2'
)

PHP will replace the 'title' key with the last one declared.

"songs":[{"title": "song1"}, {"title": "song2"}]

This is an array of objects, so in PHP it needs to be an array of arrays.

'favSongs' => array(
   array('title' => 'song1'),
   array('title' => 'song2')
)

answered Mar 9, 2012 at 19:59

gen_Eric

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