I want to know how to call subclass methods in the superclass.
5 Answers
I believe this is a pattern used often.
class A(object):
def x(self):
self.y()
def y(self):
print('default behavior')
class B(A):
def y(self):
print('Child B behavior')
class C(A):
def z(self):
pass
>>>B().x()
Child B behavior
>>>C().x()
default behavior
It is sort of like an abstract class, but provides default behavior. Can't remember the name of the pattern off the top of my head though.
1 Comment
Here's what I've just tried:
class A(object):
def x(self):
print self.y()
class B(A):
def y(self):
return 1
>>> B().x()
1
So unless you had some specific problem, just call a method from the subclass in the base class and it should just work.
7 Comments
A be a base class which can be extended in, say, 3 or 4 ways. It doesn't know how these are implemented, only which signature they provide. I've seen such things often, e.g. in MySQLdb.This is a very broad question. As you don't provide example code, I'll just show the easiest example:
class A(object):
def meth1(self, a):
self.meth2(a, a*a)
class B(A):
def meth2(self, a, b):
return b / a
b = B()
b.meth1(10)
4 Comments
file2.py is not used at all. If you do testcase = TestCase() and testcase.execute(), it should work.I think this is related to using abstract methods. The parent class defines methods that the subclass should implement and the parent class knows that these methods will be implemented. Similar structures exist for example in Java.
Using these in Python is discussed here well: Abstract methods in Python