Simple for-loop in shell script

Question

I have a cvs repository with different modules. The setup is always the same:

/data/cvs/<repo>/CVSROOT/passwd

I need to have a short script that loops over all repositories and performs this command:

grep "^iq" <repo>/CVSROOT/passwd | sort | uniq

The purpose is to have all usernames that start with the prefix "iq". The output will be a list with usernames, passwordhashes and the cvsmodule:

iqabcde:5!h8kdh2937slj:cvsabc

This output should be split by using ":" as terminator. I need to have 3 variables that I can access.

To be honest I don't have a lot of knowledge in shell scripting. Would be great if anyone could help, because I think this is solvable.

Thanks a lot

Ignacio Vazquez-Abrams · Accepted Answer · 2012-02-02 09:52:03Z

1

I'm bored.

#!/bin/bash
for repo in /data/cvs/*
do
  IFS=: read username hash module < <(grep "^iq" "$repo"/CVSROOT/passwd | sort | uniq)
  echo "Name: $username, Hash: $hash, Module: $module"
done

answered Feb 2, 2012 at 9:52

Ignacio Vazquez-Abrams

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5 Comments

nimrod Over a year ago

thanks a lot for this. Most of the time I get "Name: , Hash: , Module:" as output. I suppose it is because some password hashes contain special characters? The password hash always contains 13 characters.

Ignacio Vazquez-Abrams Over a year ago

Weird. Which specific lines result in that?

nimrod Over a year ago

e.g. hashes like "mE7YHNejLCviM" work, hashes like "JXfFZCZrL.6HY | JW9/ydvBFO482 | 5!b4RlH/IgYzI" don't work.

nimrod Over a year ago

can we "hardcode" the password hash to contain exactly 13 characters?

nimrod Over a year ago

it works when I use nawk: for repo in /data/cvs/* do grep "^iq" "$repo"/CVSROOT/passwd | sort |uniq | nawk -F ':' '{print "Name: " $1 ", Hash: " $2 ", Module: " $3 }' done

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