jQuery adding variables

Question

I have used following code to add three variables but instead of adding these variables its concatenating these variables.

var registration_fee = $('input[type="radio"][name="registration_fee"]:checked').val();
var material_fee = $('input[type="radio"][name="material_fee"]:checked').val();
var tuition_fee = $('input[type="radio"][name="tuition_fee"]:checked').val();
// alert(tuition_fee)
var total_fee = registration_fee + material_fee + tuition_fee;
$('#total_fee').html(total_fee);

leepowers · Accepted Answer · 2012-01-27 05:00:45Z

13

Cast them to numbers using parseInt or parseFloat:

var total_fee = parseInt(registration_fee) + parseInt(material_fee) + parseInt(tuition_fee);

answered Jan 27, 2012 at 5:00

leepowers

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4 Comments

Rahul Singh Over a year ago

BUt if I have used ,val() whats need to parse it than?

nnnnnn Over a year ago

Or if you want something more compact you can always use the unary plus operator. I'd suggest doing the conversion from string to number at the time you set the variable values, so like this: var tuition_fee = +$('input[type="radio"][name="tuition_fee"]:checked').val(); (etc.) - note the '+' before the '$'.

Andrew Whitaker Over a year ago

You should always specify the radix when using parseInt

leepowers Over a year ago

You should always specify the radix when accepting user-typed numbers. If your system doesn't generate hex or octal numbers you'll be fine.

Sudhir Bastakoti · Accepted Answer · 2012-01-27 05:01:16Z

2

Try:


var total_fee = parseInt(registration_fee, 10) + parseInt(material_fee, 10) + parseInt(tuition_fee, 10);

Or parseFloat, whichever suits

answered Jan 27, 2012 at 5:01

Sudhir Bastakoti

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Comments

riyas2806299 · Accepted Answer · 2013-10-30 06:25:04Z

2

Try

Cast them to numbers using Number

tal_fee = Number(registration_fee) + Number(material_fee) + Number(tuition_fee);

answered Oct 30, 2013 at 6:25

riyas2806299

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Comments

xdazz · Accepted Answer · 2012-01-27 05:01:47Z

1

Use parseInt to turn the string to int, or parseFloat for float.

answered Jan 27, 2012 at 5:01

xdazz

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Comments

subindas pm · Accepted Answer · 2017-08-25 12:01:29Z

0

Try to use parseInt(price) + parseInt(ticket_buyer_fee) for the variables it works

answered Aug 25, 2017 at 12:01

subindas pm

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