I need to verify input which is like en-US or en-us or ar-AE I have searched net and found it bit difficult to understand and create one regular expressing on string which is no more than 5 characters in length and should be case in-sensitive.
I created one [a-z][a-z][-][a-z][a-z] this one works fine but it doesn't check the length
it will match en-USXYZ also
Regards
This is what anchors are for:
(?i)^[a-z]{2}-[a-z]{2}$
The case-insensitive option (?i) can also be set when compiling the regex:
Regex regexObj = new Regex("^[a-z]{2}-[a-z]{2}$", RegexOptions.IgnoreCase);
Use such one:
^[a-z]{2}-[a-z]{2}$
Try this:
^[a-z][a-z][-][a-z][a-z]$
Use this regular expression:
^[a-z]{2}-[a-z]{2}$
You use ^ and $ to specify the start and end of the string.
^[a-z][a-z]-[a-z][a-z]$
Or using multiplier:
^[a-z]{2}-[a-z]{2}$
You would also have to include the A-Z interval for upper case characters, unless you have specified case insensetivity for the Regex object:
^[A-Za-z]{2}-[A-Za-z]{2}$
You should use anchors in your expression:
^[a-z][a-z][-][a-z][a-z]$
\w{2}[-]\w{2} should do the trick:
\w -> character
{2} -> exact 2 times
EDIT: \w also allows number so [a-z]{2}[-][a-zA-Z]{2}
zh-Hans- Chinese (Simplified)). Also, some cultures has three parts, such assr-Cyrl-BA- Serbian, Cyrillic alphabet (Bosnia and Herzegovina).