Sort an array composed by alphanumeric strings

Question

I have an array in which the elements have like ID value "imm1", "imm2", "imm3"..."imm10"

the problem is that the sortOn method consider "imm10" lower than "imm2" because it consider 1 and 0 separatly. Then I tryed to write

immarray.sortOn("id", Array.NUMERIC)

but it don't apply the order correctly and I don't know why... maybe because my ID propriety have an alphanumeric value? Then, how I can sort i t correctly?

I want this result:

imm1
imm2
imm3
...
imm10
imm11
imm12
etc...

are there any other prefixes other than "imm"?

J. Holmes
– J. Holmes

2012-01-14 17:36:27 +00:00
Commented Jan 14, 2012 at 17:36 — J. Holmes
– J. Holmes, Commented Jan 14, 2012 at 17:36

RIAstar · Accepted Answer · 2012-01-14 14:25:23Z

2

You'll have to create a custom sorting function. In that function you'll have to select the numeric values in the Strings and sort on them. In short:

immarray.sort(sortNumeric);

private function sortNumeric(a:String, b:String):int {
    return a.match(/\d+/g)[0] - b.match(/\d+/g)[0];
}

Some explanation: the regular expression \d+ finds the numeric characters in the String. Note that this example is not programmed defensively and assumes that every String is formatted in the same way (e.g. 'imm10').

answered Jan 14, 2012 at 14:25

RIAstar

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