142

How do I remove the carriage return character (\r) and the Unix newline character(\n) from the end of a string?

Improve this question
0

13 Answers 13

Reset to default
233

This will trim off any combination of carriage returns and newlines from the end of s:

s = s.TrimEnd(new char[] { '\r', '\n' });

Edit: Or as JP kindly points out, you can spell that more succinctly as:

s = s.TrimEnd('\r', '\n');
Improve this answer
Sign up to request clarification or add additional context in comments.

7 Comments

Take note of the params keyword in the declaration of TrimEnd, it let's you pass multiple instances of a character instead of the array. msdn.microsoft.com/en-us/library/w5zay9db(VS.71).aspx
How about this: s = s.TrimEnd(System.Environment.NewLine.ToCharArray());
I've been writing c# since v1.0 came out (10 years ago). Now you tell me about TrimEnd. Doh!
Just out of interest, all you really need is s = s.TrimEnd() - as the docs say: If trimChars is null or an empty array, Unicode white-space characters are removed instead. - see String.TrimEnd
@StuartWood: ...which is not what Avik asked for. He asked specifically for '\r' and '\n' and nothing else, not the space character ' ' for instance.
|
35

This should work ...

var tst = "12345\n\n\r\n\r\r";
var res = tst.TrimEnd( '\r', '\n' );
Improve this answer

Comments

23 
String temp = s.Replace("\r\n","").Trim();

s being the original string. (Note capitals)

Improve this answer

5 Comments

That will also: 1) Remove \r\n from the middle of the string, 2) Remove any whitespace characters from the start of the string, and 3) remove any whitespace characters from the end of the string.
True, I assumed only one /r/n at the end. It wasn't mentioned in the orginal post. I'm not sure that warrents a -1 vote
Is using replace() then trim() not overkill when TrimEnd() can do the job alone, or am I missing something?
great suggestion @MattBaker
It's better separate in this mode, s.Replace("\n","").Replace("\r","").trim()
21

If you are using multiple platforms you are safer using this method.

value.TrimEnd(System.Environment.NewLine.ToCharArray());

It will account for different newline and carriage-return characters.

Improve this answer

3 Comments

JP's method -- tst.TrimEnd( '\r', '\n' ) -- is reasonably "safe" in practice since major EOLs are [currently] just different combos of \r and \n, but alexw's is the "right" answer. Let the CLR tell you what chars are in this platform's newline. EOL hasn't always been combos of 0Ds and 0As
I used to use Environment.NewLine but it didn't seem to handle instances where \r was present without \n. TrimEnd('r','\n') seems to be more reliable in this case.
It could be that this is actually a cross-platform issue, and dec needs to specifically remove both \r \n, irrespective of what the system environment says.
11 
s.TrimEnd();

The above is all I needed to remove '\r\n' from the end of my string.

The upvoted answer seems wrong to me. Firstly, it didn't work when I tried, secondly, if it did work I would expect that s.TrimEnd('\r', '\n') would only remove either a '\r' or a '\n', so I'd have to run it over my string twice - once for when '\n' was at the end and the second time for when '\r' was at the end (now that the '\n' was removed).

Improve this answer

1 Comment

This does work to remove \r and \n but will also remove all white space, so in some cases may go too far. Note the doc for this method: " If trimChars is null or an empty array, Unicode white-space characters are removed instead."
4

If there's always a single CRLF, then:

myString = myString.Substring(0, myString.Length - 2);

If it may or may not have it, then:

Regex re = new Regex("\r\n$");
re.Replace(myString, "");

Both of these (by design), will remove at most a single CRLF. Cache the regex for performance.

Improve this answer

Comments

4

For us VBers:

TrimEnd(New Char() {ControlChars.Cr, ControlChars.Lf})
Improve this answer

Comments

4 
string k = "This is my\r\nugly string. I want\r\nto change this. Please \r\n help!";
k = System.Text.RegularExpressions.Regex.Replace(k, @"\r\n+", " ");
Improve this answer

Comments

3

This was too easy -- for me I'm filtering out certain email items. I'm writing my own custom email junk filter. With \r and/or \n in the string it was wiping out all items instead of filtering.

So, I just did filter = filter.Remove('\n') and filter = filter.Remove('\r'). I'm making my filter such that an end user can use Notepad to directly edit the file so there's no telling where these characters might embed themselves -- could be other than at the start or end of the string. So removing them all does it.

The other entries all work but Remove might be the easiest?

I learned quite a bit more about Regex from this post -- pretty cool work with its use here.

Improve this answer

1 Comment

Looks like you could do just filter = filter.Remove('\n').Remove('\r');
2

I use lots of erasing level

String donen = "lots of stupid whitespaces and new lines and others..."

//Remove multilines
donen = Regex.Replace(donen, @"^\s+$[\r\n]*", "", RegexOptions.Multiline);
//remove multi whitespaces
RegexOptions options = RegexOptions.None;
Regex regex = new Regex("[ ]{2,}", options);
donen = regex.Replace(donen, " ");
//remove tabs
char tab = '\u0009';
donen = donen.Replace(tab.ToString(), "");
//remove endoffile newlines
donen = donen.TrimEnd('\r', '\n');
//to be sure erase new lines again from another perspective
donen.Replace(Environment.NewLine, "");

and now we have a clean one row

Improve this answer

Comments

2

This is what I got to work for me.

s.Replace("\r","").Replace("\n","")
Improve this answer

Comments

0 
varName.replace(/[\r\n]/mg, '')
Improve this answer

Comments

0

If you use the nuget IvanStoychev.Useful.String.Extensions you can do:

s = s.TrimEnd(Environment.Newline);

It adds an overload of TrimEnd that takes a string.

Improve this answer

Comments

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.