Getting object variable using string + variable

Question

I would like to do something like this: echo $myObject->value_$id but I don't know proper syntax and I'm not sure if it is possible.

$id is some PHP variable, for example has value 1. In the end, I would like to get $myObject->value_1 but the number part (1) should be dynamic.

$myObject->myArray["element"]; or $myObject->myArray[$id];. I think using arrays is a better way to do this anyways. But, what exactly do you want to do? — omnidan
– omnidan, Commented Dec 28, 2011 at 15:16
Ah, ok, now I understand that 'array thing' you were talking about — simPod
– simPod, Commented Dec 28, 2011 at 15:40

LeGEC · Accepted Answer · 2014-01-14 09:25:27Z

24

The feature is called variable properties:

<?php

$myObject = (object)NULL;
$myObject->value_1 = 'I am value nr 1';

$id = 1;
echo $myObject->{"value_$id"};

edited Jan 14, 2014 at 9:25

LeGEC

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answered Dec 28, 2011 at 15:13

Álvaro González

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3 Comments

Armin Over a year ago

I have never seen before casting NULL to an object ^^ Interesting idea ;-)

Álvaro González Over a year ago

@Armin - Hang around StackOverflow for a while and you'll see weirder things :)

MacKinley Smith Over a year ago

Been writing PHP for quite a while and haven't seen this done before. You learn something new every day I suppose. Thank you very much for this knowledge. :)

Armin · Accepted Answer · 2011-12-28 15:10:29Z

5

This works:

$variableName = 'value_whatever_1337';
echo $myObject->$variableName;

answered Dec 28, 2011 at 15:10

Armin

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2 Comments

simPod Over a year ago

And can't I join variable and string in the second line somehow?

Armin Over a year ago

You could, but this is not the recommended way if you want to keep your code clear and easy to read!

Sjoerd · Accepted Answer · 2011-12-28 15:10:20Z

4

$name = "value_" . $id;
echo $myObject->$name;

answered Dec 28, 2011 at 15:10

Sjoerd

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1 Comment

simPod Over a year ago

And can't I join variable and string in the second line somehow?

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