Given the following array
[60, 1456]
How can I determine which items in this object do not have a corresponding id to the numbers in the array?
[
{id: 60, itemName: 'Main Location - Cleveland'},
{id: 1453, itemName: 'Second Location - Cleveland'},
{id: 1456, itemName: 'Third Location - New York'}
]
Use filter() combined with includes() to check if the id does not (!) exists in the ids array:
const ids = [60, 1456];
const data = [
{id: 60, itemName: 'Main Location - Cleveland'},
{id: 1453, itemName: 'Second Location - Cleveland'},
{id: 1456, itemName: 'Third Location - New York'}
];
const res = data.filter(({ id }) => !ids.includes(id));
console.log(res);
You can try combination of filter & includes or filter & find or filter indexOf
const a = [60, 1456];
const b = [
{id: 60, itemName: 'Main Location - Cleveland'},
{id: 1453, itemName: 'Second Location - Cleveland'},
{id: 1456, itemName: 'Third Location - New York'}
];
const idExists = b.filter(ob => {
// const includes = !a.includes(ob.id);
const find = a.find(id => id !== ob.id);
return find;
})
// Efficient approach
const mapOfIds = a.reduce(acc, id => {...acc, [id]: id}, {});
const idExists = b.filter(ob => !mapOfIds[ob.id]);
filter()andincludes()? Please show us your attempt....