Regex to match pattern "Double-Double;"

Question

I have trouble finding a regex matching this pattern:

A numeric (decimal separator can be . or ,), followed by
a dash -, followed by
a numeric (decimal separator can be . or ,), followed by
a semi-column or a space character

This pattern can be repeated one or more time.

The following examples should match the regex:

1-2;
1-2;3-4;5-6;
1,0-2;
1.0-2;
1,0-2.0;
1-2 3-4;
1-2 3,00-4;5.0-6;

The following examples should not match the regex:

1-2
1 2;
1_2;
1-2;3-4

1 2; appears in both the list of items that should match and the list of items that shouldn't match. — Utensil
– Utensil, Commented Sep 30, 2011 at 16:17
@Utensil Again a mistake from me! I should read what I wrote. Thanks! — Otiel
– Otiel, Commented Sep 30, 2011 at 16:19

Jacob Eggers · Accepted Answer · 2011-09-30 18:31:51Z

2

Edit updated based on moving of 1 2; to non-match.

This should work:

@"^(\d+([,.]\d+)?-\d+([,.]\d+)?[ ;])+(?<=;)$"

Explanation

^              //Start of the string.
(              //Start of group to be repeated. You can also use (?=
\d+            //One or more digits.
([,.]\d+)?     //With an optional decimal
-              //Separated by a dash
\d+([,.]\d+)?  //Same as before.
[ ;]           //Terminated by a semi-colon or a space
)+             //One or more of these groups.
(?<=;)         //The last char before the end needs to be a semi-colon
$              //End of string.

edited Sep 30, 2011 at 18:31

answered Sep 30, 2011 at 16:22

Jacob Eggers

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4 Comments

Ben Voigt Over a year ago

Looks good, except I don't think space is an alternative to dash, looks like it can only be used in place of a semicolon.

Joe Over a year ago

You don't have to escape the . inside brackets

Jacob Eggers Over a year ago

@IAbs Thanks, I always forget about that. Fixed now.

Otiel Over a year ago

Thanks that works. I updated my question after your answer so it does not quite answer it now, but I managed to adapt it: @"^([0-9]+([,.][0-9]+)?[-][0-9]+([,.][0-9]+)?[ ;])+(?<=;)$"

Mark Byers · Accepted Answer · 2011-09-30 16:13:57Z

1

Try this:

@"^([\d.,]+-[\d.,]+[ ;])*[\d.,]+-[\d.,]+;$"

Note that [\d.,]+ accepts some character sequences which wouldn't normally be considered valid "numeric" values such as 00..,.,. You might want to find a better regular expression to match numeric values and substitute it into the regular expression.

answered Sep 30, 2011 at 16:13

Mark Byers

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1 Comment

Jacob Eggers Over a year ago

+1 @Joey But this is a little better: (0|[1-9]\d*) otherwise, it won't accept 10

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