How do I select rows from a DataFrame based on multi conditions

Question

I have a pandas DataFrame that looks:

df=pd.DataFrame({'user': ['user 1', 'user 4', 'user 1', 'user 4', 'user 1', 'user 4'],
                 'group': [0, 0, 1, 1, 2, 2],
                'x1': [0.9, 0.9, 0.7, 0.7, 0.4, 0.4],
                'x2': [0.759740, 1.106061, 0.619357, 1.260234, 0.540633, 1.437956]})

output:

    user  group  x1    x2
0   user 1  0   0.9 0.759740
1   user 4  0   0.9 1.106061
2   user 1  1   0.7 0.619357
3   user 4  1   0.7 1.260234
4   user 1  2   0.4 0.540633
5   user 4  2   0.4 1.437956

I want to return each user with a condition if x2 is below x1 then return this row and if there is no row that meets this condition when x2 is below x1 then return this user with a change group number to 10.

For example: for the user1, row number 2 should be selected since it returns a min value of x2 below x1 1 and even row 4 has a min value of x2 but x2 is higher than x1. for user 4, all x2 higher than x1 for all rows, so we change group number for min value of x2 to number 10.

The expected output:

jezrael · Accepted Answer · 2023-01-05 11:28:31Z

Use:

df2 = (df[df['x2'].lt(df['x1'])]
           .set_index('group')
           .groupby('user')['x2']
           .idxmin()
           .reindex(df['user'].unique(), fill_value=10)
           .reset_index(name='group'))
print (df2)

     user  group
0  user 1      1
1  user 4     10

How it working:

First filter rows by condition in boolean indexing:

print (df[df['x2'].lt(df['x1'])])
     user  group   x1        x2
0  user 1      0  0.9  0.759740
2  user 1      1  0.7  0.619357

Then get group names by minimal x2 per groups by DataFrameGroupBy.idxmin, so used DataFrame.set_index:

print (df[df['x2'].lt(df['x1'])].set_index('group'))
         user   x1        x2
group                       
0      user 1  0.9  0.759740
1      user 1  0.7  0.619357

And then add missing users by unique values in Series.reindex:

print (df[df['x2'].lt(df['x1'])].set_index('group').groupby('user')['x2'].idxmin())
user
user 1     1
Name: x2, dtype: int64

print (df[df['x2'].lt(df['x1'])].set_index('group')
        .groupby('user')['x2'].idxmin()
        .reindex(df['user'].unique(), fill_value=10))
user
user 1     1
user 4    10
Name: x2, dtype: int64

And last create 2 columns DataFrame by Series.reset_index.

thank you but in output, we should replace (x2) with a group!!
@alxander21 - oops, you are right, answer was edited. By .reset_index(name='group')
thank you, could we save this series into a dataframe with two columns (user and group)? this is my expected output.

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