53

I need to evaluate a custom function passed from the server as a string. It's all part of a complicated json I get, but anyway, I seem to be needing something along the lines:

var customJSfromServer = "return 2+2+2;"
var evalValue = eval(customJSfromServer);
alert(evalValue) ;// should be "6";

Obviously this is not working as I expected. Any way I can achieve this ?

8 Answers 8

102

The first method is to delete return keywords and the semicolon:

var expression = '2+2+2';
var result = eval('(' + expression + ')')
alert(result);

note the '(' and ')' is a must.

or you can make it a function:

var expression = 'return 2+2+2;'
var result = eval('(function() {' + expression + '}())');
alert(result);

even simpler, do not use eval:

var expression = 'return 2+2+2;';
var result = new Function(expression)();
alert(result);
Sign up to request clarification or add additional context in comments.

2 Comments

Thanks for this. In your second example, the eval('(function() {' + expression + '}())'); fails in case there is a comment on the last line of the expression, with an error like unexpected end of input. To fix it, add a newline to the end: '\n}())'.
Thanks for the solution ,i used second example ,with a new line '\n}())' at the end and it worked fine.
11

If you can guarantee the return statement will always exist, you might find the following more appropriate:

var customJSfromServer = "return 2+2+2;"
var asFunc = new Function(customJSfromServer);
alert(asFunc()) ;// should be "6";

Of course, you could also do:

var customJSfromServer = "return 2+2+2;"
var evalValue = (new Function(customJSfromServer)());
alert(evalValue) ;// should be "6";

Comments

3
var customJSfromServer = "2+2+2;"
var evalValue = eval(customJSfromServer);
alert(evalValue) ;// should be "6";

Comments

2

There should not be return statement , as eval will read this as statment and will not return value.

var customJSfromServer = "2+2+2;"
var evalValue = eval( customJSfromServer );
alert(evalValue) ;// should be "6";

see http://www.w3schools.com/jsref/jsref_eval.asp

1 Comment

That probably also works if you declare evalValue outside of the string.
2

This works:

function answer() {
    return 42;
}

var a = eval('answer()');
console.log(a);

You need to wrap the return inside a function and it should pass the value on from the eval.

Comments

1

Modify server response to get "2+2+2" (remove "return") and try this:

var myvar = eval(response);
alert(myvar);

Comments

0

use anonymous function

let str = 'return 2+2+2'
let res = new Function(str)()
console.log(res) // 6

let fn = new Function('e','return e+e+e')
    res = fn(3)
console.log(res) // 9

Comments

-2

In 2019 using Template Literals:

var customJSfromServer = "2+2+2;"
var evalValue = eval(`${customJSfromServer}`);
alert(evalValue) ;// should be "6";

Comments

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.