310

Is there a better way to get the type of a variable in JS than typeof? It works fine when you do:

> typeof 1
"number"
> typeof "hello"
"string"

But it's useless when you try:

> typeof [1,2]
"object"
>r = new RegExp(/./)
/./
> typeof r
"function"

I know of instanceof, but this requires you to know the type beforehand.

> [1,2] instanceof Array
true
> r instanceof RegExp
true

Is there a better way?

3
  • 1
    FYI, the typeof new RegExp(/./); // "function" issue in Chrome appears to be fixed in Chrome 14. Commented Sep 12, 2011 at 18:36
  • 2
    possible duplicate of How do I get the name of an object's type in JavaScript? Commented Sep 12, 2011 at 18:45
  • 1
    Warning: If you're minifying your JS and you're using 'custom objects' such as typescript classes then some of the answers below will end up giving you the obfuscated function name such as n instead of the expected original name. eg constructor.name might give you n instead of the expected full name Commented Mar 8, 2017 at 0:18

14 Answers 14

263

Angus Croll recently wrote an interesting blog post about this -

http://javascriptweblog.wordpress.com/2011/08/08/fixing-the-javascript-typeof-operator/

He goes through the pros and cons of the various methods then defines a new method 'toType' -

var toType = function(obj) {
  return ({}).toString.call(obj).match(/\s([a-zA-Z]+)/)[1].toLowerCase()
}
Sign up to request clarification or add additional context in comments.

6 Comments

Interesting side note here - this could potentially break where a "host" object is passed to the function. Internet Explorer ActiveXObject instances, for example.
If you created your own object type (prototypal inheritance), how could you get it to return a more specific value than "object"? This was also raised as an issue here, but was never addressed.
If your type naming contains : or _ you may extend this regex to match(/\s([a-z,_,:,A-Z]+)/)
The regex would also need to include numbers for things like Uint8Array. Instead, consider the more general match(/\s([^\]]+)/) which should handle anything.
I'd suggest to use the \w word operator instead…
|
68

You can try using constructor.name.

[].constructor.name
new RegExp().constructor.name

As with everything JavaScript, someone will eventually invariably point that this is somehow evil, so here is a link to an answer that covers this pretty well.

An alternative is to use Object.prototype.toString.call

Object.prototype.toString.call([])
Object.prototype.toString.call(/./)

5 Comments

name is an extension to ECMAScript and will not work in all browsers.
Answer up-voted due to confirming suspicion that everything done in javascript is somehow evil.
EVIL: if you're minifying your code then constructor.name can likely end up being something like n instead of the object name you expect. So watch out for that - especially if you only minify in production.
null and undefined unfortunately don't have a constructor.
JavaScript itself is evil. And silly. The fact that this question has no good answer is the living proof of that.
53

You may find the following function useful:

function typeOf(obj) {
  return {}.toString.call(obj).split(' ')[1].slice(0, -1).toLowerCase();
}

Or in ES7 (comment if further improvements)

const { toString } = Object.prototype;

function typeOf(obj) {
  const stringified = obj::toString();
  const type = stringified.split(' ')[1].slice(0, -1);
      
  return type.toLowerCase();
}

Results:

typeOf(); //undefined
typeOf(null); //null
typeOf(NaN); //number
typeOf(5); //number
typeOf({}); //object
typeOf([]); //array
typeOf(''); //string
typeOf(function () {}); //function
typeOf(/a/) //regexp
typeOf(new Date()) //date
typeOf(new Error) //error
typeOf(Promise.resolve()) //promise
typeOf(function *() {}) //generatorfunction
typeOf(new WeakMap()) //weakmap
typeOf(new Map()) //map
typeOf(async function() {}) //asyncfunction

Thanks @johnrees for notifying me of: error, promise, generatorfunction

8 Comments

Thanks for this. It also works for date objects: typeOf(new Date())
Ah, I'd forgotten about that - thank you, it's now included.
And typeOf(Promise.resolve())//promise typeOf(function *() {})//generatorfunction
I can't get this answer to work in typescript. Gives error: [ts] Cannot redeclare block-scoped variable 'toString'
Not sure about TypeScript. Have you tried the ES7 version? toString not being explicitly declared might be the cause?
|
42

A reasonably good type capture function is the one used by YUI3:

var TYPES = {
    'undefined'        : 'undefined',
    'number'           : 'number',
    'boolean'          : 'boolean',
    'string'           : 'string',
    '[object Function]': 'function',
    '[object RegExp]'  : 'regexp',
    '[object Array]'   : 'array',
    '[object Date]'    : 'date',
    '[object Error]'   : 'error'
},
TOSTRING = Object.prototype.toString;

function type(o) {
    return TYPES[typeof o] || TYPES[TOSTRING.call(o)] || (o ? 'object' : 'null');
};

This captures many of the primitives provided by javascript, but you can always add more by modifying the TYPES object. Note that typeof HTMLElementCollection in Safari will report function, but type(HTMLElementCollection) will return object

Comments

16

Also we can change a little example from ipr101

Object.prototype.toType = function() {
  return ({}).toString.call(this).match(/\s([a-zA-Z]+)/)[1].toLowerCase()
}

and call as

"aaa".toType(); // 'string'

1 Comment

Remember kids, manipulating JavaScript base objects can lead to compatibility and other weird issues. Try to use this sparingly in both libraries and larger projects!
13

one line function:

function type(obj) {
    return Object.prototype.toString.call(obj).replace(/^\[object (.+)\]$/,"$1").toLowerCase()
}

this give the same result as jQuery.type()

Comments

6

You can apply Object.prototype.toString to any object:

var toString = Object.prototype.toString;

console.log(toString.call([]));
//-> [object Array]

console.log(toString.call(/reg/g));
//-> [object RegExp]

console.log(toString.call({}));
//-> [object Object]

This works well in all browsers, with the exception of IE - when calling this on a variable obtained from another window it will just spit out [object Object].

3 Comments

@Xeon I think the hatred against IE is a bit too much. IE9 is a much better browser than its predecessors.
@pessimopoppotamus but nobody who would update their browser to IE9 uses IE.
IE 9 is a step in the right direction, IE 10 is looking pretty good. Incidentally, the bug I mentioned was a regression in IE 9 - they fixed it in IE 8.
4

My 2¢! Really, part of the reason I'm throwing this up here, despite the long list of answers, is to provide a little more all in one type solution and get some feed back in the future on how to expand it to include more real types.

With the following solution, as aforementioned, I combined a couple of solutions found here, as well as incorporate a fix for returning a value of jQuery on jQuery defined object if available. I also append the method to the native Object prototype. I know that is often taboo, as it could interfere with other such extensions, but I leave that to user beware. If you don't like this way of doing it, simply copy the base function anywhere you like and replace all variables of this with an argument parameter to pass in (such as arguments[0]).

;(function() {  //  Object.realType
    function realType(toLower) {
        var r = typeof this;
        try {
            if (window.hasOwnProperty('jQuery') && this.constructor && this.constructor == jQuery) r = 'jQuery';
            else r = this.constructor && this.constructor.name ? this.constructor.name : Object.prototype.toString.call(this).slice(8, -1);
        }
        catch(e) { if (this['toString']) r = this.toString().slice(8, -1); }
        return !toLower ? r : r.toLowerCase();
    }
    Object['defineProperty'] && !Object.prototype.hasOwnProperty('realType')
        ? Object.defineProperty(Object.prototype, 'realType', { value: realType }) : Object.prototype['realType'] = realType;
})();

Then simply use with ease, like so:

obj.realType()  //  would return 'Object'
obj.realType(true)  //  would return 'object'

Note: There is 1 argument passable. If is bool of true, then the return will always be in lowercase.

More Examples:

true.realType();                            //  "Boolean"
var a = 4; a.realType();                    //  "Number"
$('div:first').realType();                   // "jQuery"
document.createElement('div').realType()    //  "HTMLDivElement"

If you have anything to add that maybe helpful, such as defining when an object was created with another library (Moo, Proto, Yui, Dojo, etc...) please feel free to comment or edit this and keep it going to be more accurate and precise. OR roll on over to the GitHub I made for it and let me know. You'll also find a quick link to a cdn min file there.

1 Comment

If you do (null).realType() it gives Uncaught TypeError: Cannot read properties of null (reading 'realType')
3
function getType(obj) {
    if(obj && obj.constructor && obj.constructor.name) {
        return obj.constructor.name;
    }
    return Object.prototype.toString.call(obj).slice(8, -1).toLowerCase();
}

In my preliminary tests, this is working pretty well. The first case will print the name of any object created with "new", and the 2nd case should catch everything else.

I'm using (8, -1) because I'm assuming that the result is always going to start with [object and end with ] but I'm not certain that's true in every scenario.

Comments

3

This version is a more complete one:

const typeOf = obj => {
  let type = ({}).toString.call(obj).match(/\s([a-zA-Z]+)/)[1]
  if (type === 'Object') {
    const results = (/^(function|class)\s+(\w+)/).exec(obj.constructor.toString())
    type = (results && results.length > 2) ? results[2] : ''
  }
  return type.toLowerCase()
}

Now not only you can have these results: (as they've been answered here)

undefined or empty -> undefined
null -> null
NaN -> number
5 -> number
{} -> object
[] -> array
'' -> string
function () {} -> function
/a/ -> regexp
new Date() -> date
new Error -> error
Promise.resolve() -> promise
function *() {} -> generatorfunction
new WeakMap() -> weakmap
new Map() -> map

But also you can get the type of every instance or object you construct from classes or functions: (which is not valid between other answers, all of them return object)

class C {
  constructor() {
    this.a = 1
  }
}

function F() {
  this.b = 'Foad'
}

typeOf(new C()) // -> c
typeOf(new F()) // -> f

1 Comment

Hi, I see maybe one possible improvement (but questionable) -> if the function return custom defined classname/objectName it should be probably case-sensitive, return exact name.
2

I guess the most universal solution here - is to check for undefined and null first, then just call constructor.name.toLowerCase().

const getType = v =>
  v === undefined
    ? 'undefined'
    : v === null
      ? 'null'
      : v.constructor.name.toLowerCase();




console.log(getType(undefined)); // 'undefined'
console.log(getType(null)); // 'null'
console.log(getType('')); // 'string'
console.log(getType([])); // 'array'
console.log(getType({})); // 'object'
console.log(getType(new Set())); // `set'
console.log(getType(Promise.resolve())); // `promise'
console.log(getType(new Map())); // `map'

2 Comments

As far I know - the .constructor.name always contains the string value. For undefined/null we have the appropriate strings returned by the function.
Since constructor is an inherited property, this breaks for objects created with Object.create(null). Simple enough to fix, but what to call it? "[object null]" ?
2

I've made this function:

( You should name it more unique so it doesn't collide with some other global name. )

function type(theThing) {
    return Object.prototype.toString.call(theThing).match(/\s([\w]+)/)[1].toLowerCase()
}
type({})           //-> 'object'
type([])           //-> 'array'
type(function(){}) //-> 'function'
    
type(null)         //-> 'null'
type(undefined)    //-> 'undefined
type(true)         //-> 'boolean'
type('hello')      //-> 'string'
type(42)           //-> 'number'

type(Symbol())     //-> 'symbol'
type(/abc/)        //-> 'regexp'
type(new Set())    //-> 'set'
// etc ...

PS: F.NiX above made more robust version that also tell you the name of your custom objects made from Class or constructor function.

Comments

0

https://npmjs.com/package/advanced-type

I created a package for this purpose.

Comments

-3

typeof condition is used to check variable type, if you are check variable type in if-else condition e.g.

if(typeof Varaible_Name "undefined")
{

}

Comments

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.