Python: script's directory

Question

I was looking for a solution, but have not found what I need.

Script path: /dir/to/script/script.py or C:\dir\script.py

Excepted result:

$ ./script.py
output: /dir/to/script
$ cd .. && ./script/script.py
output: /dir/to/script

Is there any function in os module or something?

I mixed solutions and write:

print os.path.abspath(os.path.dirname(__file__))

But it's ugly. Is there better way?

Mu Qiao · Accepted Answer · 2011-09-03 15:01:04Z

15

os.path.realpath will give you the result:

os.path.dirname(os.path.realpath(__file__))

edited Sep 3, 2011 at 15:01

answered Sep 3, 2011 at 14:13

Mu Qiao

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2 Comments

wim Over a year ago

the question asked for the script dirname. all realpath does is eliminate symbolic links and then return os.path.abspath

wim Over a year ago

it is still fragile and assumes certain things about the cwd and where the script was executed from. for example, put os.chdir('/tmp') in the line above in the script and this solution can break.

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