String-split into array of objects

Question

I am trying to split a string into an array of objects in TS. I have the following (example) string:

Example1,Example2,Example3,Example4,Example5

And I'm trying to parse it into:

    [
       {
          "id":"Example1"
       },
       {
          "id":"Example2"
       },
       {
          "id":"Example3"
       },
       {
          "id":"Example4"
       },
       {
          "id":"Example5"
       }
    ]

using split() i can easily split it into an array of strings, but that doesn't quite cover my use case in this instance. Can anyone help me out?

Does this answer your question? JS : Convert Array of Strings to Array of Objects — VLAZ
– VLAZ, Commented May 12, 2022 at 11:21

Pedro Feltrin · Accepted Answer · 2022-05-12 11:21:50Z

1

Take a look at the JavaScript Array method map. You can perform any transformation over array items with it, such as turning them into plain objects.

Mdn docs on Array.map

In your case, you want something like: myString.split(",").map(el => ({ id: el });

answered May 12, 2022 at 11:21

Pedro Feltrin

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Oluwayomi Balogun · Accepted Answer · 2022-05-12 12:09:16Z

1

Here's your answer in typescript:

interface Output {
    id: string
}

const initialString: string = 'Example1,Example2,Example3,Example4,Example5';

const finalArray: Output[] = [].concat(initialString.split(',').map(item => {
    return { id: item }
}))

answered May 12, 2022 at 12:09

Oluwayomi Balogun

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Comments

Agus Ocampo · Accepted Answer · 2022-05-12 11:34:50Z

If your string items have always the same length, (always follow a standar format like "id1,id2,id3" or "part1.part2,part3") you could use .substring(index from, index to+1)

Like this:

var array : string[] = []; 

//string.length+4 will allow to susbtring the last item of the string
for(var n = 0; n < (string.length+4); i++){

  //taking "id1" as an example, substring from 0 - 4 whill return "id1" 
  array.push(string.substring(n, n+4));
 // adding +4 to n will make it substring from after the comma on the next 
 //iteration and return "id2"
  n += 4;

}

This way you should try to create a standar to your string items

Here's some doc to substring :

https://www.tutorialspoint.com/typescript/typescript_string_substring.htm

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