How can we extract a next numeric value to a string in python

s = "Initial: [818 v1] any other string or words here"

import re
p = re.findall(r'\d+',s)
print(p)

OUTPUT

['818','1']

But if you only want the number which has more than 1 character Then

s = "Initial: [818 v1] any other string or words here"

import re
p = re.findall(r'\d+',s)
p = list(filter(lambda e:len(e)-1,p))
print(p)

OUTPUT:

['818']

After OP wants another question answer.

string = 'Abc 1 String Xyz 3 try new 4'

string_lst = string.split()

def func(lst,e):
    if not lst[e].isdigit():
        try:
            int(lst[e+1])
        except IndexError:
            return lst[e]
        except ValueError:
            return False
        else:
            return lst[e]
    return lst[e]

lst = [func(string_lst,a) for a in range(len(string_lst))]

string_list = list(filter(lambda e:e,lst))

string_dict = {string_list[a]:int(string_list[a+1]) for a in range(0,len(string_list),2)}
print(string_dict)

Or you can try this way

import re

s = 'Abc 1 String Xyz 3 try new 4'

matches = re.findall(r'(\w+)\s*(\d+)?', s)
result = {key: int(value) for key, value in matches if value}

print(result)

OUTPUT

{'Abc': 1, 'Xyz': 3, 'new': 4}