PHP AJAX POST send multiple variables

Question

with an ajax post to php can i send multiple variables, and if so whats the syntax?

loadXMLDoc("scripts/product_transfer.php?group="+group+"subgroup="+subgroup+"user="+user+,function()

something like that??

here is the function code:

//---------------------------------------------------------------------------------------------------    -----------------------------------------------------------------------
//Function to handle ajax
function loadXMLDoc(url,cfunc)
{
if (window.XMLHttpRequest)
  {// code for IE7+, Firefox, Chrome, Opera, Safari
  xmlhttp=new XMLHttpRequest();
  }
else
  {// code for IE6, IE5
  xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
xmlhttp.onreadystatechange=cfunc;
xmlhttp.open("POST",url,true);
xmlhttp.send();
}

Is there a specific reason why you're not using a library to make Ajax requests easier? — Pekka
– Pekka, Commented Aug 26, 2011 at 10:27
@Pekka ... that's how learning is done. For every other reason, you are right, of course. — ty812
– ty812, Commented Aug 26, 2011 at 10:28
i dont know about creating a library to make Ajax requests easier, im still new to ajax. for now can i ask can i do this and if so what is the correct syntax? — David
– David, Commented Aug 26, 2011 at 10:29
Just add & group="+group+"&subgroup= and boom you have multiple variables. — Dreaded semicolon
– Dreaded semicolon, Commented Aug 26, 2011 at 10:29
@Martin yeah, it's fine to do this on ground level for learning purposes, of course. But it's often that people just follow the wrong (years-old) tutorials — Pekka
– Pekka, Commented Aug 26, 2011 at 10:29

nobody · Accepted Answer · 2011-08-26 10:53:26Z

6

Yes you can but you have forgotten the &s between values. You can also send data with POST method as argument to send() method. Also don't forget to use encodeURIComponent() on string values:

xmlhttp.open( "POST", url, true );
xmlhttp.send( "group="+encodeURIComponent(group)+
              "&subgroup="+encodeURIComponent(subgroup)+
              "&user="+encodeURIComponent(user) );

answered Aug 26, 2011 at 10:53

nobody

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Comments

Andrej · Accepted Answer · 2011-08-26 10:30:15Z

1

You should add & or '&amp'; between different variables in query string like

scripts/product_transfer.php?group="+group+"&subgroup="+subgroup+"&user="+user

answered Aug 26, 2011 at 10:30

Andrej

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Comments

Ashley · Accepted Answer · 2011-08-26 10:38:36Z

1

Try this!

loadXMLDoc("scripts/product_transfer.php?group="+group+"&subgroup="+subgroup+"&user="+user+, function() { //Code to run when data is sent back});

answered Aug 26, 2011 at 10:38

Ashley

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Comments

user2155518 · Accepted Answer · 2013-04-29 05:35:02Z

i have written code for this and its work well,

page-1.

<select name="qt_n1" id="qt_n1" style="width: 100px;" onchange="return q1mrks(this.value,<?php echo $gen1_marks; ?>)">
                                <option>No. of Que.</option>
                                <?php
                                    for($i=1;$i<=25;$i++){?>
                                        <option value="<?php echo $i; ?>"><?php echo $i; ?></option>
                                <?php } ?>
                            </select>

page-2.js

function q1mrks(country,m)
{
  // alert("hellow");
if (country.length==0)
  {
   //alert("hellow"); 
  document.getElementById("q1mrks").innerHTML="";
  return;
  }
if (window.XMLHttpRequest)
  {// code for IE7+, Firefox, Chrome, Opera, Safari
  xmlhttp=new XMLHttpRequest();
  }
else
  {// code for IE6, IE5
  xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
xmlhttp.onreadystatechange=function()
  {
  if (xmlhttp.readyState==4 && xmlhttp.status==200)
    {
    document.getElementById("q1mrks").innerHTML=xmlhttp.responseText;
    }
  }
xmlhttp.open("GET","../location/cal_marks.php?q1mrks="+country+"&marks="+m,true);

//mygetrequest.open("GET", "basicform.php?name="+namevalue+"&age="+agevalue, true)
xmlhttp.send();
}

and simply i got the values on the third page

page-3.php

<?php 
    echo $Q1mrks = $_GET['q1mrks'];
    echo $marks = $_GET['marks'];
?>
<div id="q1mrks"></div>

Thank You,

kleopatra · Accepted Answer · 2013-12-24 10:19:43Z

0

data="postvarname1="+varvalue+"postvarname2"+var

& so on.....

edited Dec 24, 2013 at 10:19

kleopatra

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answered Dec 24, 2013 at 10:17

Amol

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