How to print only once in loop?

Question

b = input().split(' ')
c = list(map(int,b))
y = 0
for i in range(len(b)):
    if c[i] %2 == 0:
        print(c[i])
        y = 1
    elif i == len(c) - 1 & y == 0:
        print('No number that is divisible by 2')

Code takes a list of numbers as input, then it prints all values divisible by 2, but if there are no such values it should print about this only once. My code works properly only in certain cases. I know another implementation but i need solution within 1 loop

If you only want to print once, don't do it in the loop. Put it after the loop. — Barmar
– Barmar, Commented Apr 16, 2022 at 22:16

Andrey · Accepted Answer · 2022-04-16 22:16:32Z

2

Add break:

b = input().split(' ')
c = list(map(int,b))
y = 0
for i in range(len(b)):
    if c[i] %2 == 0:
        print(c[i])
        y = 1
    elif i == len(c) - 1 & y == 0:
        print('No number that is divisible by 2')
        break

answered Apr 16, 2022 at 22:16

Andrey

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1 Comment

Mr.Proper Over a year ago

thx, but problem was that i used '&' instead of 'and'

Pi Marillion · Accepted Answer · 2022-04-17 01:39:49Z

0

You may want to simplify by calculating the numbers divisible by 2 first, then deciding what to print:

nums = map(int, input().split(' '))
div2 = [i for i in nums if not i % 2]
if div2:
    for i in div2:
        print(i)
else:
    print('No number that is divisible by 2')

answered Apr 17, 2022 at 1:39

Pi Marillion

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