Creating new array of objects from specific values in 2 different arrays (JavaScript)

Question

I got these 2 arrays:

const data = [
  { url: 'google.com', title: 'google', social: false, corporate: true },
  { url: 'facebook.com', title: 'facebook', social: true, corporate: true }
 ];

const valuesToExtract = ['url', 'title'];

I need to get to this result:

const result = [
 { url: 'somepath[0].url', title: 'somepath[0].title' },
 { url: 'somepath[1].url', title: 'somepath[1].title' }
]

I tried this way:

const newArray = [];    
for (let i = 0; i < data.length; i++) {
  for (const value of valuesToExtract ) {
    const newObject = {};
      newObject[value] = `somepath[${i}].${value}`;
      newArray.push(newObject);
  }
}

But the result I get is:

const result = [
  { url: 'somepath[0].url' },
  { title: 'somepath[0].title' },
  { url: 'somepath[1].url' },
  { title: 'somepath[1].title' }
]

How can I do it better?

Bao Huynh · Accepted Answer · 2022-04-13 17:15:37Z

Just need to change a bit of where to put stuff in your nested loops. You need two loops:

The first loop goes over the data array
For every data point, the 2nd loop goes over the valuesToExtract

Therefore, you only want to push your newObject once the 2nd loop has finished (meaning once valuesToExtract has finished extracting). This way, you get a newObject for every data item.

const data = [
  { url: 'google.com', title: 'google', social: false, corporate: true },
  { url: 'facebook.com', title: 'facebook', social: true, corporate: true }
 ];

const valuesToExtract = ['url', 'title'];
const newArray = [];    
for (let i = 0; i < data.length; i++) {
  // Create a new Object for every data item
  const newObject = {};
  for (const value of valuesToExtract ) {
      newObject[value] = `somepath[${i}].${value}`;
  }
  newArray.push(newObject);
}

console.log(newArray)

Collectives™ on Stack Overflow

Creating new array of objects from specific values in 2 different arrays (JavaScript)

1 Answer 1

Comments

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Related