React-native Linking.openUrl doesn't open link to another screen

Question

I have a react-native app and I'm trying to "redirect" user to another screen(based on url received from a deep linking", for example, if an user is on Screen A, then exits the app, clicks on the link, Screen A opens up and from Screen A the user should be redirected to the screen B. I'm getting the deep link on the screen A but can't redirect user to Screen B on android. My code:

Linking.openURL(deepLink)

The deeplink has this structure:

myApp://mainPage/address

When I use Linking.canOpenURL => it throws an error. I can't seem to figure out what I'm doing wrong, any suggestion is appreciated.thank you

new_reactjs · Accepted Answer · 2022-03-31 02:21:54Z

0

Solved: posting here in case anyone else runs into the same issue - I changed Linking.openURL(deepLink) to branch.openURL(deepLink) and it worked

answered Mar 31, 2022 at 2:21

new_reactjs

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4 Comments

justbecause Over a year ago

what's branch here? It's not clear.

hndvf Over a year ago

@justbecause probably branch.io

Humayun Kabir Over a year ago

Where did you get branch from?

Julio Orellana Over a year ago

what is branch???????? I can't find it on react native nor react navigation

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