How to extract a certain text from a string using Python

Question

Consider I have a string in the format

sampleapp-ABCD-1234-us-eg-123456789. I need to extract the text ABCD-1234. Its more like I need ABCD and then the numbers before the -

Please let me know how can i do that

Answer 1

You could use string.split(), so it would be:

string = 'sampleapp-ABCD-1234-us-eg-123456789'
example = string.split('-')

Then you can access 'abcd' and '1234' as example[1] and example[2] respectively. You can also join them back together into one string if needs be with string.join().

string = 'sampleapp-ABCD-1234-us-eg-123456789'
example = string.split('-')

newstring = ' '.join(example[1:3])
print (newstring)

You can also change the seperator, '-'.join would make it so the output is 'ABCD-1234' rather than 'ABCD 1234'.

Answer 2

You can use Regex (Regular expression) Here's the Python script you can use:

import re

txt = "sampleapp-ABCD-1234-us-eg-123456789"
x = re.findall("([ABCD]+[-][0-9]+)", txt)
print(x)

More varied version:

x = re.findall("([A-Z]{4}[-][0-9]+)", txt)

For more info about Regex you can learn it here: regexr.com

Hope this helps. Cheer!

Answer 3

You can do that :

txt = "sampleapp-ABCD-1234-us-eg-123456789"
abcd = txt[10:14]
digits = txt[15:19]
print(abcd)
print(digits)

You can also use split the text using txt.split("-") and then you can extract what you want :

abcd = txt.split("-")[1]
digits = txt.split("-")[2]

Answer 4

Please keep this post as an enquiry if it doesn't answer your question.

If what your are saying is that the string is of the form a-B-X0-c-d-X1 and that you want to extract B-X0 from the string then you can do the following:

text =  'a-B-X0-c-d-X1'
extracted_val = '-'.join(text.split('-')[1:3])