create a variable in a struct and access the variable in the same struct

Question

I'm trying to add a custom font to a swift project and have a question for Swift's struct. Since I'm gonna make custom fonts with different sizes and I need to use string ("My custom font") multiple times, I want to make a variable for the strings but get the error.

struct Fonts {

    let myFont = "My custom font"
    let myFontBold = "My custom font bold"

    static let customFontNormal = UIFont(name: self.myFont, size: 16.0)
    static let customFontBold = UIFont(name: self.myFontBold, size: 16.0)
}

and I get this error message

Cannot use instance member 'myFont' within property initializer; property initializers run before 'self' is available.

I want to call the font like Fonts.customFontNormal or something similar, but is there a way to make a string variable and enable to access the value from a variable in the same struct?

Why would you use static for some of this, but not all? Unrelated, the type is enum Font, not struct Fonts. But why bother making a type instead of just extending UIFont? — user652038
– user652038, Commented Nov 4, 2021 at 3:19
Thank you Jessy. Sorry I'm still a beginner of Swift stuff and I just followed Sean Allen's video to make a custom UI. youtu.be/C4f7R2gUO8E?t=279 — Yuuu
– Yuuu, Commented Nov 4, 2021 at 3:25
In the video, he only makes a fonts title for the struct but that was my misunderstanding. — Yuuu
– Yuuu, Commented Nov 4, 2021 at 3:27

Yuuu · Accepted Answer · 2021-11-04 03:43:22Z

2

Thanks to Jessy, I extend UIFont and add a new struct for the sting.

struct Fonts {

    static let myFont = "myFont"
    static let myFontBold = "myFontBold"
}


extension UIFont {

    static func myFontNormal() -> UIFont {
        return UIFont(name: Fonts.myFont, size: 16)!
    }

    static func myFontBoldNormal() -> UIFont {
        return UIFont(name: Fonts.myFontBold, size: 16)!
    }
}

Thanks a lot!

answered Nov 4, 2021 at 3:43

Yuuu

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