Instead of the typical binary 0 or 1, or two consecutive numbers, I need to create a loop which will generate three random -1s and 1s, 100 times. My code so far looks like:
new = []
i =1
while i <= 100:
random = np.random.randint(low=-1, high=1, size=(1,3))
new.append(random)
i += 1
print(new.append(random))
Though this just returns None and even if it was working, would return 0s as well which is not wanted.
No need to bother importing numpy - it may be easier to just use random.choices() (from the standard library) to generate three random choices from [-1, 1], and do it 100 times.
import random
new = [random.choices([-1, 1], k=3) for _ in range(100)]
# [[1, 1, -1],
# [1, 1, 1],
# [1, 1, -1],
# [-1, -1, -1],
# ...
# [1, -1, 1]]
If you're doing this inside a function, with the intent for that function to produce new for outside use, then don't forget to do return new at the end of the function.
print(new)? Here you're just printing the function return value of another.append()call, which will beNone