How to filter an array of objects based on value

Question

I have an array of objects:

The object looks like this:

applicationNumber: "35028"
denomination: "ZippIT"
denominationNature: "Denomination"
denominationStatus: "SURRENDERED"
publicationCountry: "RU"
publicationType: "PBR"
speciesName: "Triticum aestivum L."

I want to be able to filter that array of objects based on a string. If that string is on any of the values of the object, we return the object.

Any idea on where to start from?

What about const filteredArray = originalArray.filter(item => !Object.values(item).includes('yourstring'))? — secan
– secan, Commented Aug 5, 2021 at 13:43
Yes, if any of them. And normally the keys are dynamic. So Giovanni's solution won't work for me... — Sonhja
– Sonhja, Commented Aug 5, 2021 at 13:44
@Sonhja I canceled but you didn't say that keys could be dynamic — Giovanni Esposito
– Giovanni Esposito, Commented Aug 5, 2021 at 13:45
@secan I think the OP want the string as a positive indicator to keep the object, so I think you don't need the ! (which would exclude objects with that string); otherwise, looks like a solid solution — apsillers
– apsillers, Commented Aug 5, 2021 at 13:45

lejlun · Accepted Answer · 2021-08-05 13:45:16Z

2

I suppose you're looking for a combination of Array#filter and Object.values.

Something like this:

let includesString = arrayOfObjs.filter(object => 
  Object.values(object).includes(targetString)
)

Demo:

let arrayOfObjs = [
  {value1: "target", value2: "not a target"},
  {value3: "also not a target", value4: "target"},
  {value5: "nope"},
  {value6: "target"}
]

let objectsWithTargets = arrayOfObjs.filter(object => 
  Object.values(object).includes("target")
)

console.log(objectsWithTargets)

answered Aug 5, 2021 at 13:45

lejlun

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