Repeat one python script with different inputs 1 to 100

Question

I have python script a.py and it takes integer input I want to repeat this script with different input integers from 1 to 10. Usually I do create a1.py to a10.py with integer hard-corded but i want to run them without creating a1.py to a10.py

Edit:

I have script test.py

import sys
count = sys.argv[1]
print(count)

#I use this count value as an input for running further script

I want to run python test.py 2 after python test.py 1 finishes and so on. So I naively use this command: python test.py 1 && python test.py 2 && python test.py 3 && and so on... up to python test.py 10

Is there any short way to write this long command.

You can use command line arguments. realpython.com/python-command-line-arguments — Yoshikage Kira
– Yoshikage Kira, Commented Jun 11, 2021 at 9:09

Dmitry Rusanov · Accepted Answer · 2021-06-11 09:17:17Z

1

You can use sys.argv for getting parameters. And run the file passing the parameter to the function python my_file.py 10.

import sys


def run_range():
    count = sys.argv[1]
    for i in range(int(count)):
        print(i)


if __name__ == '__main__':
    run_range()

answered Jun 11, 2021 at 9:17

Dmitry Rusanov

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Comments

Arib Muhtasim · Accepted Answer · 2021-06-11 09:15:24Z

0

You can do something similar to this:

def myFunc(x):
    print(f"HALLO {x}")

for x in range(0, 11):
    myFunc(x)

answered Jun 11, 2021 at 9:15

Arib Muhtasim

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1 Comment

Jack Olien Over a year ago

my python script is memory intensive. Hence, I cannot keep running all in one python script by looping.

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