Trying make a loop with Selenium in Python

I have a code to search in this site --> https://osu.ppy.sh/beatmapsets?m=0 only maps with difficulty that i want, but i can't make a loop right

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.wait import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.action_chains import ActionChains
from time import sleep

# Set link and path
driver = webdriver.Chrome(executable_path=r"C:\Users\Gabri\anaconda3\chromedriver.exe")
driver.get("https://osu.ppy.sh/beatmapsets?m=0")
wait = WebDriverWait(driver, 20)

# Variables, lists and accountants
lista = {}
links, difficulty, maps2, final = [], [], [], []
line, column, = 1, 1
link_test = ''

n = int(input('insert how many maps do you want: '))
c = 1

# Open link in Chrome and search map by map
while True:
    if c > n:
        break
    sleep(1)
    wait.until(EC.element_to_be_clickable(
        (By.CSS_SELECTOR, f".beatmapsets__items-row:nth-of-type(1)>.beatmapsets__item:nth-of-type(1)")))
    games = driver.find_element_by_css_selector(
        f".beatmapsets__items-row:nth-of-type({line}) .beatmapsets__item:nth-of-type({column}) .beatmapset-panel__info-row--extra")
    actions = ActionChains(driver)
    actions.move_to_element(games).perform()
    wait.until(EC.visibility_of_element_located((By.CSS_SELECTOR, ".beatmaps-popup__group")))
    scores = driver.find_elements_by_css_selector(
        ".beatmaps-popup__group .beatmaps-popup-item__col.beatmaps-popup-item__col--difficulty")

    # This part i can't makes automatic, for example, if i wanted to show 6 maps i would have to add 2 more if's
    # Changing the variable (line) and (column) accordingly

    # I liked to have a loop with 'while' or 'for ... in' but i don't know how make it
    # I tried to do a question before start the code like 'how many maps do you want?' and this number would be the times that code would execute
    # But no work it =(

    if c % 2 != 0:
        column = 2
        if c % 2 == 0:
            line += 1
    else:
        line += 1
        column = 1

        # Convert string to float (difficulty numbers)
    for score in scores:
        a = score.text
        b = a.replace(',', '.')
        difficulty.append(float(b))

    # Save in list 'links' each link corresponding of map that is printing
    games.click()
    sleep(3)
    link_test = driver.current_url
    links.append(link_test)
    link_test = ''
    driver.back()

    # Dict with map, link and difficulty
    lista = {
        'map': f"{c}",
        'link': f"{links}",
        'difficulty': f"{difficulty}"}
    c += 1
    # Print each map in dict 'lista'
    print(f"Map: {lista['map']}\nLink: {links}\nDifficulty: {lista['difficulty']}\n")

    # This part is my filter, if map have difficulty 6.00 or more, it's add to list 'final' for download
    for b in difficulty:
        if b >= 6.00:
            # This slice, the link had printing error 'TypeError: unhashable type: 'list'', i found this way to solve it
            # I know that is not the best way to solve this error, but at least i tried =,)
            xam = str(links[0])
            xam1 = xam.replace("'", '')
            xam2 = xam1.replace("[", '')
            xam3 = xam2.replace("]", '')
            final.append(xam3)

    # Clean all lists for no have duplicate items in dict 'lista' when next map is selected
    difficulty.clear()
    lista.clear()
    links.clear()

# Print how many maps with difficulty 6.00 has been found
print(f'There are {len(sorted(set(final)))} maps to download')

# This question is for future download, im still coding this part, so u can ignore this =3
pergunta = input('Do you want to download them? \n[ Y ]\n[ N ]\n>>> ').lower().strip()

# Clean duplicate links and show all links already filtered
if pergunta == 'y':
    for x in final:
        maps2.append(x)
    print(sorted(set(maps2)))

In 'if's' part, i need help to make it automatic, in a way that no uses to many 'if's' like i did. With variables that add themselves with 'v += n' maybe? Idk ;-;

PS-If you find any logic errors or some way to optimize my code I will be happy to learn and fix it