Access character arrays in C

Question

why I can not assign it like this:

char c1 []="Odin";
   c1=c1+1;

Note that I include

#include<string.h>

Because you cannot assign to arrays. What do you want to do? — MikeCAT
– MikeCAT, Commented Apr 24, 2021 at 0:19
What should c1=c1+1; do? Do u want the string to go from "Odin" to "Pdin" ? Or to remove the letter O ? — Tudor
– Tudor, Commented Apr 24, 2021 at 0:22
You can do that with pointers: char c1[] = "Odin"; char* p = c1; p = p + 1; — MikeCAT
– MikeCAT, Commented Apr 24, 2021 at 0:26
@Tudor No because strcpy() with overlapped source and destination invokes undefined behavior. — MikeCAT
– MikeCAT, Commented Apr 24, 2021 at 0:27

Zoso · Accepted Answer · 2021-04-24 00:44:57Z

1

Quoting the reference for your problem:

Assignment Objects of array type cannot be modified as a whole: even though they are lvalues (e.g. an address of array can be taken), they cannot appear on the left hand side of an assignment operator:

So, since c in your code is an array object i.e. a type of an array, it cannot appear on the left-hand side of an assignment operator.

answered Apr 24, 2021 at 0:44

Zoso

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