break in for loop python program

Question

i try to make program if sum of program 1000 the program wil print finished but if the number when we input = 0 the program return error. i try it with break in python but i dont get the right output. i need your oppinion about this.

this my program
banyak = int(input('Masukan banyak angka yang ingin dimasukkan = '))
for j in range(banyak):
    A = int(input("enter the number of 1 : "))
    B = int(input("enter the number of 2 : "))
    C = int(input("enter the number  of 3 : "))
    if(A + B + C == 1000):
        print("finished")
        break
    elif(A==0 or B==0 or C==0):
        print("error")
        break

the program should input :

100
0

output:

error

input:

400
300
300

output:

finished

Please explain where the actual input is different of the expected output. For first input you give a 0 so get error, for second it sums at 1000 so you're ok, seems good to me — azro
– azro, Commented Apr 16, 2021 at 7:22
Is it the use of break that stops the loop that bother you ? If you specify a number of round to "play", you may NOT use a break, that stops the loop — azro
– azro, Commented Apr 16, 2021 at 7:24
if i input A =100 B = 0 C = 300 my program keep running until finish ask input form user. and what i want is if i input A =100 and B = 0 the program stop and does'nt ask input C again. so are if i input A = 0 the program stop and print error and doesnt ask input B and C again — ryand
– ryand, Commented Apr 16, 2021 at 7:25
Program stop OR only current iteration ? Does the game continue after printing error ? — azro
– azro, Commented Apr 16, 2021 at 7:25

azro · Accepted Answer · 2021-04-16 07:28:58Z

The easiest is to use an assert statement after each input, if it is incorrect, it'll raise an AssertionError that you can catch. The second element for assert is the exeception message, that can be use in the except section

banyak = int(input('Masukan banyak angka yang ingin dimasukkan = '))
for j in range(banyak):
    print(f"Round {j + 1}/{banyak}")
    try:
        A = int(input("enter the number of 1 : "))
        assert A != 0, "A is 0"
        B = int(input("enter the number of 2 : "))
        assert B != 0, "B is 0"
        C = int(input("enter the number  of 3 : "))
        assert C != 0, "C is 0"
        if A + B + C == 1000:
            print("finished")
            break
    except AssertionError as e:
        print("Error:", e)
        break

Masukan banyak angka yang ingin dimasukkan = 5
Round 1/5
enter the number of 1 : 200
enter the number of 2 : 300
enter the number  of 3 : 100
Round 2/5
enter the number of 1 : 400
enter the number of 2 : 0
Error: B is 0

thank you. can i have any question about another program that i made. if you want to help me, let's start the discussion in the discussion chat.

Shawn · Accepted Answer · 2021-04-16 07:30:36Z

when you input

1    # banyak
100  # A
0    # B

then the program's current line is

    C = int(input("enter the number  of 3 : "))

so it can't break. you can try this

banyak = int(input('Masukan banyak angka yang ingin dimasukkan = '))

for j in range(banyak):
    A = int(input("enter the number of 1 : "))
    if A == 0:
        print("error")

    B = int(input("enter the number of 2 : "))
    if B == 0:
        print("error")

    C = int(input("enter the number  of 3 : "))
    if C == 0:
        print("error")


    if A + B + C == 1000:
        print("finished")
        break

but is so foolish. And you can try this

banyak = int(input('Masukan banyak angka yang ingin dimasukkan = '))

for j in range(banyak):

    number_list = []
    for _ in range(3):
        input_number = int(input("enter the number : "))
        if input_number == 0:
            print("error")
            break
        number_list.append(input_number)


    if sum(number_list) == 1000:
        print("finished")
        break

    print('=============')

thank you. can i have any question about another program that i made. if you want to help me, let's start the discussion in the discussion chat?

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