why does this code return false:
var text = "3b3xx";
if(text.match("/^\d?b\d+xx$/")) {
return true;
}
return false;
I can not see any problem with my regular expression.. I want to return true, if the string starts with any numbers, followed by "b", followed by any numers, followed by "xx".
You are passing a string where a regular expression is expected.
var text = "3b3xx";
if(text.match(/^\d?b\d+xx$/)) {
return true;
}
return false;
match method will convert it to a RegExp object internally, e.g. : if (text.match("^\\d?b\\d+xx$")) but anyway, in this case is completelly unnecessary - since the pattern is fixed-, I would even return /^\d?b\d+xx$/.test(text); to remove the if statement.
RegExp object internally": not in my Chrome it won't.'a'.match('\\w')[0] == 'a'. If it doesn't work, it's an implementation bug, the behavior is completely described on the ECMAScript Specification (15.5.4.10 - see Step 4 -)RegExp object was "expected", in fact, you could pass any non-regexp object, it will be converted to String, and it will be used to build the RegExp object behind the scenes. Cheers.Why not trying this:
var text = "3b3xx";
return text.match(/^\d?b\d+xx$/);
Just lose the quotes around your regex.
Regex is an object in Javascript, not a String.
/^\d?b\d+xx$/
