How to convert a char array to a string array

Question

How do you convert a char array to a string array? Or better yet, can you take a string and convert it to a string array that contains each character of the string?

Edit: thanks @Emiam! Used his code as a temp array then used another array to get rid of the extra space and it works perfectly:

String[] tempStrings = Ext.split("");
String[] mStrings = new String[Ext.length()];

for (int i = 0; i < Ext.length(); i++) 
    mStrings[i] = tempStrings[i + 1];

Answer 1

Or better yet, can you take a string and convert it to a string array that contains each character of the string?

I think this can be done by splitting the string at "". Like this:

String [] myarray = mystring.split("");

Edit: In case you don't want the leading empty string, you would use the regex: "(?!^)"

String [] mySecondArray = mystring.split("(?!^)");

Answer 2

Beautiful Java 8 one-liner for people in the future:

String[] array = Stream.of(charArray).map(String::valueOf).toArray(String[]::new);

Answer 3

I have made the following test to check Emiam's assumption:

public static void main(String[] args) {
    String str = "abcdef";

    String [] array = str.split("");
}

It works, but it adds an empty string in position 0 of the array. So array is 7 characters long and is { "", "a", "b", "c", "d", "e", "f" }.

I have made this test with Java SE 1.6.

Answer 4

brute force:

String input = "yourstring";
int len = input.length();
String [] result = new String[len];

for(int i = 0; i < len ; i ++ ){
    result[i] = input.substring(i,i+1);
}

Answer 5

This will give string[] as result, but will have only one value as below String[] str = {"abcdef"};

Answer 6

// char[] to String[] String[] sa1 = String.valueOf(cArray).split("");